The answer to your question is
x^33
Answer:
Tessa's mistake was to have multiplied each dimension by two instead of multiplying by a square root of two.
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z -----> the scale factor
x ----> the area of the enlarged garden
y ----> the area of the original garden

we have that
If Tessa multiplies each dimension by 2, then the scale factor equals 2.

substitute

The area of the enlarged garden will be equal 4 times the area of the original garden
so
If Tessa wanted to have twice as much surface, she must multiply each dimension by a square root of 2.
therefore
Tessa's mistake was to have multiplied each dimension by two instead of multiplying by a square root of two
Answer:
D. 24
Step-by-step explanation:
Let's name the diagram
Row 1: a1, a2, a3
Row 2: b1, b2, b3
Row 3: c1, c2, c3
From the diagram,
b2 and c2 have been given
All rows, columns and diagonal must sum up to 18
If b2=6 and c2=4
a2=18-(6+4)
=18-10
=8
a2=8
Assume a1=4
Diagonals a1+b3+c3=18
4+6+c3=18
10+c3=18
c3=18-10
=8
Assume a3=6
Diagonals a3+b2+c1=18
6+6+c1=18
12+c1=18
c1=18-12
=6
So b1=18-(6+4)
=18-10
=8
b1=8
b3=18-(6+8)
=18-14
=4
b3=4
Input all the numbers into the boxes
We have,
4 8 6
8 6 4
6 4 8
Corner numbers are a1,a3,c1,c3
=4,6,6,8
Sum of all the corner numbers=4+6+6+8
=24
D. 24
Answer:
where one perfect square is subtracted from another, is called a difference of two squares. It arises when (a − b) and (a + b) are multiplied together. This is one example of what is called a special product.
Step-by-step explanation:
Every difference of squares problem can be factored as follows: a2 – b2 = (a + b)(a – b) or (a – b)(a + b). So, all you need to do to factor these types of problems is to determine what numbers squares will produce the desired results. Step 3: Determine if the remaining factors can be factored any further.