Answer:
The area of the warehouse floor is 1925yd²
The volume of the boxes is 4812.5yd³
Step-by-step explanation:
First we have to calculate the area, for this we must multiply the length by the width
a = area
l = long = 55yd
w = width = 35yd
a = l * w
a = 55yd * 35yd
a = 1925yd²
to calculate the volume we have to multiply the area by the height
asks us for the volume for half the height so we have to divide the height by 2
a = area = 1925yd²
h = height = 5yd/2 = 2.5yd
v = volume
v = a * h
v = 1925yd² * 2.5yd
v = 4812.5yd³
The area of the warehouse floor is 1925yd²
The volume of the boxes is 4812.5yd³
71.3 UK£
Step-by-step explanation:
Both x and y are 79 degrees because vertical angles are congruent.
B u A = 48
B = 45
The part of set B not included in A is B - A∩B = 45 - 7 = 38
Since B u A = 48, A must have 48-38 = 10 elements (3 exclusive of B, 7 shared with B).
------
Alternatively, the inclusion-exclusion principle may be used: A + B - (A ∩ B) = A u B
A + 45 - 7 = 48
A = 48 - 45 + 7
A = 10
NOTE that I'm using A and B to indicate the number of elements in each set, respectively.
More formally, one would write |A| and |B| to indicate the cardinality (number of elements) of the set.
Multiply the average by the number of tests to find the total of the scores:
82 x 3 = 246
88 x 3 = 264
The total of the three tests would need to be between 246 and 264
The total of the first two tests is 79 + 85 = 164
Subtract the total of the first two from the totals above:
246 - 164 = 82
264 - 164 = 100
The score of the third test needs to be between 82 and 100