All categories

4 years ago

What numbers multiply to -48 and add to 2 at the same time

Mathematics

2 answers:

Murljashka [212]4 years ago

7 0

Answer:

-6 and 8

Step-by-step explanation:

-6 x 8 is -48 and -6 + 8 is 2

Whitepunk [10]4 years ago

4 0

Answer: 8(-6) = -48

8 + -6 = 2

You might be interested in

18+

OLga [1]

Answer:

I will answer this for you if you put this into understandable terms.

4 0

3 years ago

Write the slope-intercept form of the equation of the line given a slope of 3 and a y-intercept

Eduardwww [97]

Y=3x-4

There you go my friend. Please consider brainliest

5 0

3 years ago

Evaluate each of the following. (a) P(11,5) (b) C(11,5) (a) P(11,5) = (Simplify your answer.) (b) C(11,5) = (Simplify your answe

Hunter-Best [27]

<h2>Answer:</h2>

(a) P(11,5)= 55440

(b) C(11,5)=462

<h2>Step-by-step explanation:</h2>

We know that the permutation is the number of ways of arranging r items out of a total of n items and is given by:

$P(n,r)=\dfrac{n!}{(n-r)!}$

and the combination is the number of ways of choosing r items out of a total of n items and is given by:

$C(n,r)=\dfrac{n!}{r!\times (n-r)!}$

(a)

P(11,5)

$P(11,5)=\dfrac{11!}{(11-5)!}\\\\P(11,5)=\dfrac{11!}{6!}\\\\P(11,5)=\dfrac{11\times 10\times 9\times 8\times 7\times 6!}{6!}\\\\P(11,5)=11\times 10\times 9\times 8\times 7\\\\P(11,5)=55440$

(b)

C(11,5)

$C(11,5)=\dfrac{11!}{5!\times (11-5)!}\\\\C(11,5)=\dfrac{11!}{5!\times 6!}\\\\C(11,5)=\dfrac{11\times 10\times 9\times 8\times 7\times 6!}{5\times 4\times 3\times 2\times 1\times 6!}\\\\C(11,5)=462$

8 0

3 years ago

Prove that: (Sec A- cosec A)(1+ tan A+cot A) = tan A× sec A - cot A × cosec A

mash [69]

Answer:

Step-by-step explanation:

$(sec A-cosecA)(1+tanA+cotA)=tanAsecA-cotAcosecA$

we take the LHS so here goes,

$(sec A-cosecA)(1+tanA+cotA)=tanAsecA-cotAcosecA\\(\frac{1}{cosA} -\frac{1}{sinA})(1+\frac{sinA}{cosA}+\frac{cosA}{sinA})\\\\(\frac{sinA-cosA}{sinAcosA})(\frac{sinAcosA+sin^2A+cos^2A}{sinAcosA})\\$

since , $sin^2A+cos^2A=1$

the identity becomes,

$(\frac{sinA-cosA}{sinAcosA})(\frac{1+sinAcosA}{sinAcosA})\\\\(\frac{sinA+sin^2AcosA-cosA-cos^2AsinA}{sin^2Acos^2A})\\\\$

now, we know,

$sin^2A=1-cos^2A$ and $cos^2A=1-sin^2A$

the identity becomes,

$(\frac{sinA+(1-cos^2A)cosA-cosA-(1-sin^2A)sinA}{sin^2Acos^2A} )\\\\$

$(\frac{sinA+cosA-cos^3A-cosA-sinA+sin^3A}{sin^2Acos^2A})$

sin A and cos A cancel out it becomes zero

$\frac{sin^3A-cos^3A}{sin^2Acos^2A} \\\\$

Splitting the denominator the identity becomes

$\frac{sin^3A}{sin^2Acos^2A}-\frac{cos^3A}{sin^2Acos^2A} \\\\\frac{sinA}{cos^2A} - \frac{cosA}{sin^2A} \\\\\frac{sinA}{cosA}(\frac{1}{cosA})-\frac{cosA}{sinA}(\frac{1}{sinA})\\\\$

Hence,

$tanAsecA-cotAcosecA$

3 0

3 years ago

The rectangle below has an area of 81-x^2 square meters and a width of 9-x meters. What expression represents the length of the

Vinvika [58]

Answer:

idk sorry

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers