-2(5x + 16)+ 12 = 50

2 answers:

6 0

Subtract 12 from both sides
-2(5x+16)=50-12

Simplify 50-12 to 38
-2(5x+16)=38

Divide both sides by -2
5x+16=-38/2

Simplify 38/2 to 19
5x+16=-19

Subtract 16 from both sides
5x=-19-16

Simplify-19-16 to -35
5x=-35

Divide both sides by 5
x=-35/5

Simplify 35/5 to 7
x=-7

Hope this helps! :)

ArbitrLikvidat [17]2 years ago

4 0

X will equal -7 in this problem

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igomit [66]

Answer:

b = -30

Step-by-step explanation:

-b/5 - 27 = -21

~Add 27 to both sides

-1/5b = 6

~Multiply -5 to both sides

b = -30

Best of Luck!

8 0

3 years ago

The proof that point (1,root 3) lies on the circle that is centered at the origin and contains the point (0,2) is found in the t

AURORKA [14]

<h2>Answer:</h2>

D. Distance formula

<h2>Step-by-step explanation:</h2>

$The \ \mathbf{distance} \ d \ between \ the \ \mathbf{points} \ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ in \ the \ plane \ is:\\ \\ d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

As in the statement:

<em>The distance form</em> $(0,0)$ to $(0,2)$ is $\sqrt{(0-0)^2+(2-0)^2}=\sqrt{2^2}=2$ <em>whose justification is the </em><em>Distance Formula. </em>

<em />

Here in this statement the justification is also the Distance Fromula, so we take the distance from $(0,0) \ to \ (1,\sqrt{2})$ whose result is also 2 and is the radius of the circle.