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3 years ago

Simplify the following expressions ( use distributed property )

Mathematics

1 answer:

oksian1 [2.3K]3 years ago

6 0

-9+3x

2(9-3x)/-2

-(9-3x)

-9+3x

Brainliest?

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Short Response

garik1379 [7]

Answer:

(a)2(89x+84)

(b) $2(89x+84-x^2\pi)$

Step-by-step explanation:

The dimensions of the larger rectangular field are:

Length=5x + 12; Width = 9x + 14.

The dimensions of the smaller rectangular soccer field are:

Length=5x; Width = 9x.

(a)Area of the part of the field that is outside the soccer field

=Area of the larger rectangular field - Area of the Soccer Field

=(5x+12)(9x+14)-5x(9x)

=(5x)(9x)+70x+108x+168-5x(9x)

=178x+168

=2(89x+84)

(b)Radius of the Semicircular Fountain =2x

From Part (a),

Area of the larger rectangular field - Area of the Soccer Field=178x+168

Area of the Semicircular Fountain = $\dfrac{\pi r^2}{2} =\dfrac{\pi (2x)^2}{2} =\dfrac{4x^2\pi}{2} =2x^2\pi$

Area of the Field that does not include the soccer field or the fountain.

=Area of the larger rectangular field - Area of the Soccer Field-Area of the Semicircular Fountain

$=178x+168-2x^2\pi\\=2(89x+84-x^2\pi)$

8 0

4 years ago

Solve: 2x2-x = 21 {-7/2,3} {-3, 7/2}

Sergio039 [100]

Answer:

The answer is (-3,7/2)

Step-by-step explanation:

$2 {x}^{2} - x - 21 = 0 \\ (2x - 7)(x + 3) = 0 \\ 2x - 7 = 0 \: \: \: or \: \: x + 3 = 0 \\ x = \frac{7}{2} \: \: and \: x = - 3$

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4 0

3 years ago

Simplify the square root of -121?

poizon [28]

Answer:

11<em>i</em>

Step-by-step explanation:

first you have to get a postive root.

$\sqrt{-121} \\ \sqrt{-1} \sqrt{121} \\$

then you solve the square roots from there, keeping in mind the imaginary number answer to the square root of -1, <em>i</em>.

$\sqrt{-1} = i\\ \sqrt{121} =11\\ 11i$

8 0

3 years ago

Read 2 more answers

Is the answer C ; y= -3x-1

Sonja [21]

Answer:

I believe you are correct

Hope This Helps! Have A Nice Day!!

8 0

4 years ago

Read 2 more answers

An SRS of size 20 is drawn from a population that has a normal distribution. The sample has a mean of 122.5 and a standard devia

Tems11 [23]

Answer:

The value is $\sigma_{\= x} = 1.789$

Step-by-step explanation:

From the question we are told that

The sample size is n = 20

The sample mean is $\= x = 122.5$

The standard deviation is $s = 8$

Generally the standard error of the mean is mathematically represented as

$\sigma_{\= x} = \frac{s}{\sqrt{n} }$

=> $\sigma_{\= x} = \frac{8}{\sqrt{20 } }$

=> $\sigma_{\= x} = 1.789$

8 0

3 years ago