The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
<h3>How to represent the
quadratic function in standard form?</h3>
The quadratic function is given as
f(x) = -3x^2 + 6x - 2
The standard form of a quadratic function is represented as:
f(x) = ax^2 + bx + c
When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form
Where
a = -3
b = 6
c = -2
Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
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Answer:
3 + 0.25x
Step-by step answer:
1. add like terms inside the bracket 8+4=12
2. divide each term in bracket by 4
12/4 = 3
x/4 = 0.25x
Answer:
6/7
Step-by-step explanation:
apple the rule
Answer:
=24x−30
Step-by-step explanation:
=(6)(4x+−5)
=(6)(4x)+(6)(−5)
=24x−30
9514 1404 393
Answer:
x = {-0.2, 6.2}
Step-by-step explanation:
The values that go into the quadratic formula are a = 1, b = -6, c = -1.