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lesya [120]
4 years ago
10

What is 2 gallons minus 5 quarts

Mathematics
1 answer:
MariettaO [177]4 years ago
6 0
There are 4 quarts in a gallon.
In two gallons would be 8 quarts.

2 gallons - 5 quarts = 8 quarts - 5 quarts = 3 quarts.

Note: 3 quarts is 3/4 or .75 of a gallon.
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What is 123% of $938.55?<br><br> Round your answer to the nearest cent
ollegr [7]

Answer:

1154.41 (rounded)

Step-by-step explanation:

8 0
3 years ago
A vet weighs two puppies. The small puppy weighs 4 2/3 pounds. The large puppy weighs 4 2/3 times as much as the small puppy. Ho
Maksim231197 [3]
4 2/3 lbs = small puppy weight
4 2/3 times the small puppies weight = large puppy weight
          4 2/3 × 4 2/3  or 4 2/3^2  = 21.77777.... or in mixed number is 21 7/9 lbs
4 0
4 years ago
A piece of wire 25 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
fomenos

Answer:

Wire used for square is 7.55 m.

Step-by-step explanation:

Let the length of wire cut for square be 'x'.

Given:

Total length of the wire = 25 m

Length of wire for square = 'x'

Length of wire for equilateral triangle = 25-x

Now, area of square (a) = x^2

Area of equilateral triangle (e) is given as:

e=\frac{\sqrt3}{4}(25-x)^2

Now, total area (A) is given as:

A=a+e\\\\A=x^2+\frac{\sqrt3}{4}(25-x)^2

Now, in order to maximize 'A', the derivative of area with respect to 'x' must be 0.

∴ \frac{dA}{dx}=0

\frac{d}{dx}(x^2+\frac{\sqrt3}{4}(25-x)^2)=0\\\\2x-\frac{\sqrt3}{2}(25-x)=0\\\\2x+\frac{x\sqrt3}{2}=\frac{25\sqrt3}{2}\\\\x(2+\frac{\sqrt3}{2})=\frac{25\sqrt3}{2}\\\\x(4+\sqrt3)=25\sqrt3\\\\x=\frac{25\sqrt3}{4+\sqrt3}=7.55\ m

Therefore, the length of the wire that is cut for square should be 7.55 m for maximum area.

3 0
3 years ago
Write 9x² - 36x = 4y² + 24y + 36 in standard form
Kisachek [45]

Answer:

9·x² - 36·x = 4·y² + 24·y + 36 in standard form is;

(x - 2)²/2² - (y + 3)²/3² = 1

Step-by-step explanation:

The standard form of a hyperbola is given as follows;

(x - h)²/a² - (y - k)²/b² = 1 or (y - k)²/b² - (x - h)²/a² = 1

The given equation is presented as follows;

9·x² - 36·x = 4·y² + 24·y + 36

By completing the square, we get;

(3·x - 6)·(3·x - 6) - 36 = (2·y + 6)·(2·y + 6)

(3·x - 6)² - 36 = (2·y + 6)²

(3·x - 6)² - (2·y + 6)² = 36

(3·x - 6)²/36 - (2·y + 6)²/36 = 36/36 = 1

(3·x - 6)²/6² - (2·y + 6)²/6² = 1

3²·(x - 2)²/6² - 2²·(y + 3)²/6² = 1

(x - 2)²/2² - (y + 3)²/3² = 1

The equation of the hyperbola  is (x - 2)²/2² - (y + 3)²/3² = 1.

5 0
3 years ago
19 POINTSSS
jekas [21]

I believe A.) 3 times

4 0
4 years ago
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