The geometrical relationships between the straight lines ab and cd
is the straight line ab is parallel to the straight line cd
Step-by-step explanation:
Let us revise some notes:
- If a line is drawn from the origin and passes through point A (a , b), then the equation of OA = ax + by
- If a line is drawn from the origin and passes through point B (c , d), then the equation of OB = cx + dy
- To find the equation of AB subtract OB from OA, then AB = (c - a)x + (d - b)y
- The slope of line AB =

∵ oa = 2 x + 9 y
∵ ob = 4 x + 8 y
∵ ab = OB - OA
∴ ab = (4 x + 8 y) - (2 x + 9 y)
∴ ab = 4 x + 8 y - 2 x - 9 y
- Add like terms
∴ ab = (4 x - 2 x) + (8 y - 9 y)
∴ ab = 2 x + -y
∴ ab = 2 x - y
∵ The slope of ab = 
∵ Coefficient of x = 2
∵ Coefficient of y = -1
∴ The slope of ab = 
∵ cd = 4 x - 2 y
∵ Coefficient of x = 4
∵ Coefficient of y = -2
∴ The slope of cd = 
∵ Parallel lines have same slopes
∵ Slope of ab = slope of cd
∴ ab // cd
The geometrical relationships between the straight lines ab and cd
is the straight line ab is parallel to the straight line cd
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Answer:
final answer is 6/(y^8)
Step-by-step explanation:
(3y^-4) = 3/(y^4)
(2y^-4) = 2/(y^4)
3*2 = 6
Add exponents y^4+y^4 = y^8
hence 6 / (y^8)
Answer:
a-3
Step-by-step explanation:
3(2a–1)−5a =
distribute
3*2a -3*1 -5a=
6a -3 -5a
combine like terms
a-3
Answer:
Step-by-step explanation:
2x+90=7x
2x=7x-90
2x-7x=-90
-5x+-90
x=18
The first one ,to substitute 3xy from -16 ...so divided both side by 3 .so, (xy =-5.33). the second one,5xy =-20. so,divided both sides by 5 so xy = -4....