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jekas [21]
3 years ago
13

The volume of a fish tank is 70 cubic feet. If the density is 0.4 fish over feet cubed, how many fish are in the tank?

Mathematics
2 answers:
Triss [41]3 years ago
8 0

Answer:

28 fish

Step-by-step explanation:

The density here is written as fish over feet cubed, so this equation can be written as 0.4=x fish/70 cubic feet

To get x alone you must multiply 0.4 by 70 to get 28, which represents the number of fish

labwork [276]3 years ago
7 0

Answer:

28 fish is the correct answer

Step-by-step explanation:.

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3 years ago
Complete parts ​(a) through ​(c) below. ​(a) Determine the critical​ value(s) for a​ right-tailed test of a population mean at t
olga_2 [115]

Answer:

a) The critical value on this case would be t_{crit}=1.325

b) The critical value on this case would be t_{crit}=-1.345

c) The critical values on this case would be t_{crit}=\pm 2.201

Step-by-step explanation:

Part a

The system of hypothesis on this case would be:

Null hypothesis: \mu \leq \mu_0

Alternative hypothesis: \mu > \mu_0

Where \mu_0 is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, on this case that is given df=20. Since its an upper tailed test we need to find a value a such that:

P(t_{20}>a) = 0.1

And we can use excel in order to find this value with this function: "=T.INV(0.9,20)". The 0.9 is because we have 0.9 of the area on the left tail and 0.1 on the right.

The critical value on this case would be t_{crit}=1.325

Part b

The system of hypothesis on this case would be:

Null hypothesis: \mu \geq \mu_0

Alternative hypothesis: \mu < \mu_0

Where \mu_0 is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, given by:

df=n-1=15-1=14

Since its an lower tailed test we need to find b value a such that:

P(t_{14}

And we can use excel in order to find this value with this function: "=T.INV(0.1,14)". The 0.1 is because we have 0.1 of the area accumulated on the left of the distribution.

The critical value on this case would be t_{crit}=-1.345

Part c

The system of hypothesis on this case would be:

Null hypothesis: \mu = \mu_0

Alternative hypothesis: \mu \neq \mu_0

Where \mu_0 is the value that we want to test.

In order to find the critical value we need to find first the degrees of freedom, given by:

df=n-1=12-1=11

Since its a two tailed test we need to find c value a such that:

P(t_{11}>c) = 0.025 or P(t_{11}

And we can use excel in order to find this value with this function: "=T.INV(0.025,11)". The 0.025 is because we have 0.025 of the area on each tail.

The critical values on this case would be t_{crit}=\pm 2.201

5 0
3 years ago
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