Ask question

Ask question

All categories

3 years ago

7

What is the scale factor of a triangle with a vertex of A(–6, 4) that has been dilated with a center of dilation at the origin s

o the vertex of its image is A' (–24, 16)?

1 answer:

Aleksandr [31]3 years ago

4 0

The scale factors would be 4

You might be interested in

Please Can Someone Tell Me The Area??

torisob [31]

Answer:

66 I am pretty sure

Step-by-step explanation:

6 x 2 divided by 2 = 6

6 + 6 = 12 x 10 divided by 2 = 60

add them together

60 + 6 = 66

3 0

3 years ago

Gina rides her bike to work at an average of 10.4 miles per hour. She bikes 1.2 hours each day. How many miles does Gina ride ea

tatiyna

So 10.4mi = 1 hour

We need to find out how many miles 1.2 hours is.

1.) Well, the first step would be to multiply 1.2 on both sides of:
10.4mi = 1 hour

because that would make this number of miles is = to 1.2 hours which is wha we're looking for

1.2(10.4) mi = 1.2 hour

2.) Simplify
12.48 mi = 1.2 hour

3.) That means Gina rides 12.48 miles each day if she rides for 1.2 hours each day at a pace of 10.4 miles per hour :)

8 0

3 years ago

What multiplies up to 53?

Alona [7]

Answer:

13.25 × 4 = 53

Hope this helps

8 0

3 years ago

A number is increased by 35%.<br><br> The result is 324

Natali5045456 [20]

Answer:

x = 323.65

Step-by-step explanation:

A number can be represented through x.

x + 35% = 324

35% means 0.35

x + 0.35 = 324

- 0.35 - 0.35

x = 323.65

hope this helps!

4 0

3 years ago

A thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F. Af

fgiga [73]

Answer:

53.3324

Step-by-step explanation:

given that a thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F.

By Newton law of cooling we have

T(t) = $T+(T_0-T)e^{-kt}$

where T (t) is temperature at time t,T =surrounding temperature = 40, T0 =70 = initial temperature

After half minute thermometer reads 60° F. Using this we can find k

$T(0,5) = 40+(70-40)e^{-k/2} = 60\\e^{-k/2} =2/3\\-k/2 = -0.4055\\k = 0.8110$

So equation is

$T(t) = 40+(30)e^{-0.8110t}\\$

When t=1,

we get

$T(1) = 40+(30)e^{-0.8110}\\\\=53.3324$

5 0

3 years ago