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exis [7]
3 years ago
10

A caution flag on the side of a road is shape like a trapezoid. One base of the trapezoid is 1 ft shorter than the other base.Fi

nd the lengths of the base if the trapezoid is 4 ft high and has an area of 10 ft^2
Mathematics
1 answer:
EleoNora [17]3 years ago
7 0

Answer:

The lengths of the base are 2 ft and 3 ft

Step-by-step explanation:

Let one base of the trapezoid be x ft

Then the other parallel side is equal to x+1 ft

Given height of the trapezoid = 4 ft

Area of the trapezoid = 10 ft^{2}

We know that the area of trapezoid=\frac{1}{2}* (height)(sum of the parallel sides)

10=\frac{1}{2}*(4)*(x+x+1)

2x+1=5

x=2

The lengths of the base are 2 ft and 3 ft

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Leokris [45]
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6 0
3 years ago
Read 2 more answers
The school band is comprised of middle school students
iogann1982 [59]

Answer:if there are 7 HS students for every 2 MS students and there are 18 MS students...

18/2 = 9

9(7) = 63

So, there are 18 + 63 = 81 total students.

Since we had 9 parts last year also (1:8), 81/9 = 9 students are in each part. 8 students in each part are HS and one is MS.

8(9) = 72 HS students last year.

72 - 63 = 9 fewer HS students than last year.

Hope this helps!

8 0
4 years ago
How is comparing 645 and 738 is different from 645 and 649
Lesechka [4]
It's different because they have 2 different numbers<span />
5 0
3 years ago
The area of a triangle is 1,440 cm2. The base of the triangle is 5 times the height. What is the height of the triangle? 12 cm 2
GarryVolchara [31]

The area of a triangle with base 'b' and height 'h' is given by the formula:

A = \frac{1}{2} bh

It is given that the area of a triangle is 1440 cm^2.

It is given that the base of the triangle is 5 times the height.

So, b=5 \times h = 5h

We have to determine the height of the triangle.

Since, A = \frac{1}{2}bh

1440 = \frac{1}{2}(5h)h

1440 = \frac{1}{2}(5h^2)

1440 \times 2 = 5h^2

2880= 5h^2

\frac{2880}{5}= h^2

h^2=576

So, h=\sqrt{576}

So, h = 24 cm

Therefore, the height of the triangle is 24 cm.

Option 2 is the correct answer.

6 0
3 years ago
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vova2212 [387]

Step-by-step explanation:

< i'll use this too represent angle

this is only presuming that this is a parallelogram and i also don't know what those numbers mean

< ACB = < CAD         (alt <s of DA II CB)             A

< ACD = < CAB        (alt <s of DC II AB)              A

AB is common                                                     S

therefore, ∆ADC is congruent to ∆CBA

if ∆ADC is congruent to ∆CBA

then < ADC = < CBA

5 0
3 years ago
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