The probability that a student participates in both sports and drama is 
.
<h3>What is the formula for P(AUB), where A and B are any two events?</h3>
If 
and 
are any two events, then the probability of the joint event 
is given by the following formula: 
Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.
Suppose 
denotes that "a student participates in sports" and 
denotes that "a student participates in drama".
So, we have 
, 
, 
.
We want to find the probability that a student participates in both sports and drama i.e., we want to find 
.
By the above formula, we obtain:
Therefore, the probability that a student participates in both sports and drama is .
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Answer:
<em>(-6, 0) and (0, 1.5)</em>
<em></em>
Step-by-step explanation:
The equation of the line in pint slope form is expressed as;
y-y0= m(x-x0)
m is the slope
(x0, y0) is the point on the line
Given
m = 1/4
(x0, y0) = (6,3)
Substitute into the formula;
y - 3 = 1/4(x-6)
4(y-3) = x - 6
4y - 12 = x-6
4y - x = -6+12
4y - x = 6
x = 4y - 6
To get the points to plot, we will find the x and y-intercept of the resulting expression.
For the x-intercept,
at y = 0
x = 4(0) - 6
x = -6
Hence the x-intercept is at (-6, 0)
For the y-intercept,
at x = 0
0 = 4y - 6
4y = 6
y = 6/4
y = 3/2
y = 1.5
Hence the y-intercept is at (0, 1.5)
<em>Hence the required points to plot to get the required line are (-6, 0) and (0, 1.5)</em>
<em></em>
Answer:
it would be 3 yards because it went 2° to the right
Answer: (x, y) = (-5, -10)
Step-by-step explanation: too lazy
