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Naddika [18.5K]
3 years ago
11

Which expression is equivalent to 14y−12?

Mathematics
1 answer:
Anettt [7]3 years ago
7 0

Answer:

The answer is 1/4 (y-2)

Step-by-step explanation:

I got the answer correct on my test!

You might be interested in
Han's house is 450 meters from school. Lin’s house is 135 meters closer to school. How far is Lin’s house from school?
Marina86 [1]

Solution:

<u>Note that:</u>

  • Han's house = 450 m from school
  • Lin's house = (450 - 135) from school

<u>Looking at the options, we can tell that the letter "z" represents Lin. </u>

  • => z = (450 - 135)
  • => z = 450 - 135

This option matches with Option D.

Option D is correct.

6 0
2 years ago
9. (4,10) and (-2,-5)<br>Slope:​
marshall27 [118]

Answer:

-7/2

Step-by-step explanation:

y2-y1 / x2-x1

-5-10 / -2-4

-15 / -6

-7 / -2

= -7/2

4 0
3 years ago
I don't know how to do this!!​
saw5 [17]
3x-1=77 (due to exterior alternate angle)
Or, 3x=77-1
or, 3x=76
or, x=76/3
or, x=25.3
6 0
2 years ago
On the school playground, the slide is due west of the tire swing and due south of the monkey bars. If the distance between the
FinnZ [79.3K]

Answer:

Step-by-step explanation:

Draw a picture!

You get a right triangle with hypotenuse = 20 ft and horizontal leg = 12 ft

Use the Pythagorean Theorem to find the length of the vertical leg:

vertical leg = √(20²-12²) = √256 = 16 ft

5 0
3 years ago
On a morning of a day when the sun will pass directly​ overhead, the shadow of a 60​-ft building on level ground is 25 ft long.
AysviL [449]

Answer:

The shadow is decreasing at the rate of 3.55 inch/min

Step-by-step explanation:

The height of the building = 60ft

The shadow of the building on the level ground is 25ft long

Ѳ is increasing at the rate of 0.24°/min

Using SOHCAHTOA,

Tan Ѳ = opposite/ adjacent

= height of the building / length of the shadow

Tan Ѳ = h/x

X= h/tan Ѳ

Recall that tan Ѳ = sin Ѳ/cos Ѳ

X= h/x (sin Ѳ/cos Ѳ)

Differentiate with respect to t

dx/dt = (-h/sin²Ѳ)dѲ/dt

When x= 25ft

tanѲ = h/x

= 60/25

Ѳ= tan^-1(60/25)

= 67.38°

dѲ/dt= 0.24°/min

Convert the height in ft to inches

1 ft = 12 inches

Therefore, 60ft = 60*12

= 720 inches

Convert degree/min to radian/min

1°= 0.0175radian

Therefore, 0.24° = 0.24 * 0.0175

= 0.0042 radian/min

Recall that

dx/dt = (-h/sin²Ѳ)dѲ/dt

= (-720/sin²(67.38))*0.0042

= (-720/0.8521)*0.0042

-3.55 inch/min

Therefore, the rate at which the length of the shadow of the building decreases is 3.55 inches/min

8 0
3 years ago
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