Rewrite the equations of the given boundary lines:
<em>y</em> = -<em>x</em> + 1 ==> <em>x</em> + <em>y</em> = 1
<em>y</em> = -<em>x</em> + 4 ==> <em>x</em> + <em>y</em> = 4
<em>y</em> = 2<em>x</em> + 2 ==> -2<em>x</em> + <em>y</em> = 2
<em>y</em> = 2<em>x</em> + 5 ==> -2<em>x</em> + <em>y</em> = 5
This tells us the parallelogram in the <em>x</em>-<em>y</em> plane corresponds to the rectangle in the <em>u</em>-<em>v</em> plane with 1 ≤ <em>u</em> ≤ 4 and 2 ≤ <em>v</em> ≤ 5.
Compute the Jacobian determinant for this change of coordinates:
Rewrite the integrand:
The integral is then
We are supposed to assume FC and AD is straight line
let's find all the angles
you already see the right angle is 90 degrees, you got that right
striaght line is 180 degrees
90+46+EF=180
136+EF=180
minus 136 both sides
EF=44
now we got another straight line
you did get that A F=46 because it is oposite
notice: AB=BC because same angle designition
so now we use
180+46+2AB=360
2AB=134
divide 2
AB=67=BC
AC=134 degrees
CAE=134+46+44=224
ABD=180 since straight line
a. 90
b. 224
c.134
d. 180
Answer: See step by step
Step-by-step explanation: Angle 2 and 3 are vertical angles since they both share a vertex and has cross intersecting lines. Angle 6 and 7 are supplementary angles because they forma linear pair.
27%
divide one hundred thirty five but the total of five hundred and move the decimal back two places
