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Marysya12 [62]
3 years ago
11

Which statements about pentagons and hexagons are real?

Mathematics
1 answer:
Margaret [11]3 years ago
7 0
Answer choice 2 would be the correct one! If the sides were all curved they would be cylinders.

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a florist is told that 40% of the 350 flowers ordered must be red roses how many roses must be in the order
Nina [5.8K]

Answer:

140 because half which is (%50) of 350 is 175 so 40% of 350 is 140

7 0
2 years ago
Can you help me understand front end and clusters when u round​
Galina-37 [17]

Answer:

I really hope this help! Some may call it front end rounding while others call is front end estimating, even though they mean the same thing. When rounding a place value, you need to look to the number to the right of it. Example: Most often a teacher may as you round the number 452 to the nearest ten’s. That number will than be 450. But why? Well as we look at the number, we know we need to round to the nearest ten. So in our case it would be 52. Our rule to remember when rounding is 5 and higher we round-up. Since we are looking at the portion of the number 52, we go right of the tens place to find the number 2. Since the number 2 is not 5 or higher, we round down making it 50. Don’t forget to finish the problem by adding the hundreds back to the original number. Your answer for this problem is 450.

Step-by-step explanation: I really hope this helps i will post the rest in the comment!

6 0
3 years ago
Wat is thy square root of 4761
deff fn [24]

Answer:

69

Step-by-step explanation:

69 squared is 4761

7 0
3 years ago
Read 2 more answers
HI SOMEONE PLEASE HELP!!!!!!!!!!
VLD [36.1K]

acute angle and the answer looks like it would be 57.5 because acute is below 60 the other angles have a fractional portion on the angles corner so A

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3 0
3 years ago
Solve for c (c - 2h) ^ 2 = d<br> Answer now please its 100
WITCHER [35]
<h2>Hello!</h2>

\boxed{\boxed{\bf THEME:\:EQUATIONS}}

Answer:

It\:\:is\:\:c=h=-\frac{\sqrt{d}-c}{2},\:c=h=-\frac{-\sqrt{d}-c}{2}

Step-by-step explanation:

c=\left(c\:-\:2h\right)^2=d

c=c-2h=\sqrt{d}         c=c-2h=-\sqrt{d}

c=-2h=\sqrt{d}-c      c=-2h=-\sqrt{d}-c

c=h=-\frac{\sqrt{d}-c}{2}          c=h=-\frac{-\sqrt{d}-c}{2}

--------------------------------------------------------------------------------------------------------------

\heartsuit Greetings

Sincerely: <em><u>anapaulacbellido</u></em>

5 0
3 years ago
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