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Brut [27]
2 years ago
11

Express each of the following radios in the simplest form.

Mathematics
1 answer:
AURORKA [14]2 years ago
4 0

Answer:

hope it helps man

eeeed

Step-by-step explanation:

edddd

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when measuring ,100degrees Fahrenheit squat to 37.7777 degrees celsius. Round to the nearest thousandth
Gre4nikov [31]

Answer:  37.778 degrees

Step-by-step explanation:

The third digit to the right of the decimal is thousandths. If the next digit to the right of that is 5 or more, add one to the thousandths. Otherwise leave it as is. Just drop everything to the right of the place you rounded to.

7 is greater than 5, so add 1 to the 7 in the thousandths place and get

37.778

8 0
3 years ago
Write the equation of a line in slope-intercept form that goes through the points (-4, 3) and (-5, 1). Show your work.
Neporo4naja [7]
M=1-3/-5-4
M=-2/-9
M=2/9

y=2/9x+c
let y=3 and x=-4
3=2/9<span>(-4)+c
3=-8/9+c
3+8/9=c
C=35/9

y=2/9x+35/9
</span>
7 0
3 years ago
Type SSS, SAS, ASA, SAA, or HL to<br> justify why the two larger triangles are<br> congruent.
Otrada [13]

Answer:

SSS

Step-by-step explanation:

5 0
3 years ago
Witch of these has a slope of -3/4 and a y intercept of 3/2
Arada [10]

Answer:

See explanation. (Also you can write an equation several different ways so without the choices I cannot tell you which)

Step-by-step explanation:

Slope-intercept form is y=mx+b

So one way to write the equation is y=-3/4 x +3/2

There are more ways to write it.

Every line about to write is a way to write it.

Multiply both sides by 4:                 4y=-3x+6

Add 3x on both sides:               3x+4y=6

Subtract 6 on both sides:         3x+4y-6=0

There are a lot of ways to write an equation like this.

To better assist you I would need to see options.

5 0
3 years ago
find the equations of the tangents to the curve y= x(x-1)(x+2) at the points where the curve cuts the x axis
antoniya [11.8K]

First of all, we compute the points of interest, i.e. the points where the curve cuts the x axis: since the expression is already factored, we have

x(x-1)(x+2) = 0 \iff x=0\ \lor\ x-1=0\ \lor\ x+2=0

Which means that the roots are

x=0\ \lor\ x=1\ \lor\ x=-2

Next, we can expand the function definition:

y = x(x-1)(x+2) = x^3 + x^2 - 2x

In this form, it is much easier to compute the derivative:

y' = 3x^2+2x-2

If we evaluate the derivative in the points of interest, we have

y'(-2) = 6,\quad y'(0)=-2,\quad y'(1)=3

This means that we are looking for the equations of three lines, of which we know a point and the slope. The equation

y-y_0=m(x-x_0)

is what we need. The three lines are:

y-0=6(x+2) \iff y = 6x+12  This is the tangent at x = -2

y-0=-2(x-0) \iff y = -2x  This is the tangent at x = 0

y-0=3(x-1) \iff y = 3x-3  This is the tangent at x = 1

7 0
3 years ago
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