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katrin [286]
3 years ago
14

Universal Containers wants line items to be organized into pre-defined groups on the output document. The name of these pre-defi

ned groups needs to be displayed above each group in the output to identify it. Which two ways can an Admin meet this requirement?
Computers and Technology
1 answer:
devlian [24]3 years ago
5 0

Answer:

Set the Group field on the Line Items type of Template Content record.

Set the New Quote Group field on each Product record with the associated group name.

Explanation:

The two array that can be implemented are:

  • Set the Group field on the Line Items type of Template Content record.
  • Set the New Quote Group field on each Product record with the associated group name.
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List two ways that search engines and electronic databases are similar and three ways that search engines and electronic databas
antoniya [11.8K]

Answer:

Explanation: search engine uses system algorithm to search out items or information as required by the user. Example is google, chrome.

Data base are archives where information could be retrieve. Its contain information such as publications, abstract,journals.

Search engine provides wide range of information depending on you request while database are mostly for academics related materials.

Data base- A good place to generate this information is library, archivals while journal, publiications are kept while search engine can be used anywhere you have an internet facilities.

In a data base, information is searched in an organized way. The collections are already well arranged in different cubicle search engine provides wide range of information not organized.

Data base may contain more complex information not easily understood, search engine provides more elaborate answers.

Similarity of the two is that they both provide information.

They are both reliable.

School library is an example of where journals and publication are kept and can be retrived.

6 0
3 years ago
Read 2 more answers
A lot of computations involve processing a string one character at a time. Often they start
dedylja [7]

Answer:

The last character in the string processed is "t".

Explanation:

The index start from 0 and the len(fruit) is 5.

When index is 0 which is less than 5; "f" is printed

When index is 1 which is less than 5; "r" is printed

When index is 2 which is less than 5; "u" is printed

When index is 3 which is less than 5; "i" is printed

When index is 4 which is less than 5; "t" is printed

When index is 5, the condition is false; so the loop content is not executed.

Therefore, the last character traversed in the string "fruit" is "t".

3 0
3 years ago
Suppose you wish to develop a matrix-multiplication algorithm that is asymptotically faster than Strassen’s algorithm. Your algo
Kazeer [188]

Answer:

The number of subproblems are given as T(n)=a*T(n/8)+\theta(n^2) while the value of T(n) to be less than S(n) is for 342.

Explanation:

The number of subproblems are given as

T(n)=a*T(n/8)+\theta(n^2)

Asymptotic running time for Strassen’s algorithm is S(n)=\theta(n^{log(7)})

Now, when a increases, number of subproblems determines the asymptotic running time of the problem and case 1 of master theorem applies. So, in worst case, asymptotic running time of the algorithm will be

T(n)=\theta(n^{logb(a)})=\theta(n^{log8(a)})=\theta(n^{log_{2}(a^{1/3})})

Now, for T(n) to be smaller than S(n)

n^{loga^{1/3}}

So,

log(a^{(1/3)})

So,

a=342

5 0
3 years ago
Explain three tests that uses for tests normality​
Volgvan

Answer:

<h2>Methods used for test of normality of data. ... [10] There are various methods available to test the normality of the continuous data, out of them, most popular methods are Shapiro–Wilk test, Kolmogorov–Smirnov test, skewness, kurtosis, histogram, box plot, P–P Plot, Q–Q Plot, and mean with SD.</h2>

Explanation:

<h2>HOPE IT HELPS YOU</h2>
7 0
2 years ago
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Easy ;) what is another word for ram
Anni [7]
Shoved or pushed :))))))))))
3 0
3 years ago
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