T=2π/|b|. The period of an equation of the form y = a sin bx is T=2π/|b|.
In mathematics the curve that graphically represents the sine function and also that function itself is called sinusoid or sinusoid. It is a curve that describes a repetitive and smooth oscillation. It can be represented as y(x) = a sin (ωx+φ) where a is the amplitude, ω is the angular velocity with ω=2πf, (ωx+φ) is the oscillation phase, and φ the initial phase.
The period T of the sin function is T=1/f, from the equation ω=2πf we can clear f and substitute in T=1/f.
f=ω/2π
Substituting in T=1/f:
T=1/ω/2π -------> T = 2π/ω
For the example y = a sin bx, we have that a is the amplitude, b is ω and the initial phase φ = 0. So, we have that the period T of the function a sin bx is:
T=2π/|b|
Answer:
D
Step-by-step explanation:
The area of a circle can be find with this formula:
radius^2 π
in this case we have the diameter, so we have to divide it by two
radius = 16 : 2 = 8 ft
area = 8^2 π
18 = 0.45 * n
the missing number is 40
<span> 62/5 - 1/25 = 5 hours.
Jack spent 5 hours.
Jill spent 6 3/4 hours </span>
I think it’s B but I’m not for sure
