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nignag [31]
3 years ago
6

What is the period of the graph of the equation y = a sin bx?

Mathematics
1 answer:
steposvetlana [31]3 years ago
7 0

T=2π/|b|. The period of an equation of the form y = a sin bx is T=2π/|b|.

In mathematics the curve that graphically represents the sine function and also that function itself is called sinusoid or sinusoid. It is a curve that describes a repetitive and smooth oscillation. It can be represented as y(x) = a sin (ωx+φ) where a is the amplitude, ω is the angular velocity with ω=2πf, (ωx+φ) is the oscillation phase, and φ the initial phase.

The period T of the sin function is T=1/f, from the equation ω=2πf we can clear f and substitute in T=1/f.

f=ω/2π

Substituting in T=1/f:

T=1/ω/2π -------> T = 2π/ω

For the example y = a sin bx, we have that a is the amplitude, b is ω and the initial phase φ = 0. So, we have that the period T of the function a sin bx is:

T=2π/|b|

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Answer: 0.418 < p < 0.512

Step-by-step explanation: A 95% conifdence interval for a population proportion is given by:

p + z\sqrt{\frac{p(1-p)}{n} }

where:

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n is sample size

The proportion for people who said "yes" is

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For a 95% confidence interval, z = 1.96.

Calculating

0.465 + 1.96*\sqrt{\frac{0.465(0.535)}{434} }

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Interval is between:

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<u>The interval with 95% of confidence is between 0.418 and 0.512.</u>

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3 years ago
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