This question was not written properly
Complete Question
Find the minimum value of the function f(x) = 0.9x² + 3.42x - 2.4 to the nearest
hundredth.
Answer:
The minimum value for the function:
f(x) = 0.9x² + 3.42x - 2.4 is (-1.9, -5.65)
Step-by-step explanation:
Our quadratic equation =
ax² + bx + c
f(x) = 0.9x² + 3.42x - 2.4
The minimum value of x formula=
x = -b/2a
a = 0.9
b = 3.42
x = -3.42/2 × 0.9
x = -3.42/1.8
x = -1.9
We input the value x in order to get the minimum value of y
f(x) = y
f(x) = 0.9x² + 3.42x - 2.4
f(-1.9) = 0.9(-1.9)² + 3.42(-1.9) - 2.4
= 3.249 - 6.498 - 2.4
=3.249 - 8.898
= -5.649
Approximately to the nearest hundredth = -5.65
Therefore, the minimum value for the function:
f(x) = 0.9x² + 3.42x - 2.4 is (-1.9, -5.65)
