Question

Find the minimum value of the function f(x) = 0.9x2 + 3.42 – 2.4 to the nearest hundredth.

Answer 1

This question was not written properly

Complete Question

Find the minimum value of the function f(x) = 0.9x² + 3.42x - 2.4 to the nearest

hundredth.

Answer:

The minimum value for the function:

f(x) = 0.9x² + 3.42x - 2.4 is (-1.9, -5.65)

Step-by-step explanation:

Our quadratic equation =

ax² + bx + c

f(x) = 0.9x² + 3.42x - 2.4

The minimum value of x formula=

x = -b/2a

a = 0.9

b = 3.42

x = -3.42/2 × 0.9

x = -3.42/1.8

x = -1.9

We input the value x in order to get the minimum value of y

f(x) = y

f(x) = 0.9x² + 3.42x - 2.4

f(-1.9) = 0.9(-1.9)² + 3.42(-1.9) - 2.4

= 3.249 - 6.498 - 2.4

=3.249 - 8.898

= -5.649

Approximately to the nearest hundredth = -5.65

Therefore, the minimum value for the function:

f(x) = 0.9x² + 3.42x - 2.4 is (-1.9, -5.65)