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2 years ago

Write an inequality for "x".

Mathematics

1 answer:

raketka [301]2 years ago

4 0

Answer: X<-3

Step-by-step explanation: I got this becuase the open dot with the arrow point left means anything lower than -3, if it was closed (filled in) dot, it would be anything -3 and lower. But since it’s not, it’s just anything lower than -3.

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1.)which of the following actions is NOT a form of transformation

ikadub [295]

Answer:

1. d

2. d

3. c

explanation

1. reflection, rotation, and dilations are all transformations

2. congruent shapes have to have the same shape and size, meaning they also have the same angle measures

3. sometimes, shapes may have the same area and perimeter but be different

7 0

3 years ago

A minor league baseball team plays 122 games in a season. If the team won 14 more than three times as many games as they lost,

Leviafan [203]

W + L = 122
W = 3L + 14

3L + 14 + L = 122
4L + 14 = 122
4L = 122 - 14
4L = 108
L = 108/4
L = 27 <=== they lost 27 games

W = 3L + 14
W = 3(27) + 14
W = 81 + 14
W = 95 <=== they won 95 games

8 0

3 years ago

PLS ANSWER ASAPThe function f(x) = 4x + 10 models the amount of money Francis makes

Andrei [34K]

Answer:

A 18

Step-by-step explanation:

f(x) = 4x + 10

f(2) = 4(2) + 10

f(2) = 8 + 10

f(2) = 18

6 0

3 years ago

Which of the following expression is an algebraic expression<br> 23(40)<br> 25/4<br> 6x<br> 12 x 12

lianna [129]

6x is an algebraic expression

6 0

3 years ago

Read 2 more answers

Write an expression for the 12th partial sum of the series 3/2+7/3+19/6+... using summation notation

lapo4ka [179]

Answer:

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=73$

Step-by-step explanation:

$First\ term\ of\ the\ series(a_1)=\frac{3}{2}\\\\Second\ term\ of\ the\ series(a_2)=\frac{7}{3}\\\\Third\ term\ of\ the\ series(a_3)=\frac{19}{6}\\\\a_2-a_1=\frac{7}{3}-\frac{3}{2}=\frac{5}{6}\\\\a_3-a_2=\frac{19}{6}-\frac{7}{3}=\frac{5}{6}\\\\Hence\ it\ is\ an\ Arithmetic\ Series\ with\ first\ term=\frac{3}{2}\ and\ constant\ difference=\frac{5}{6}$

$a_1=\frac{3}{2}+0\times \frac{5}{6}\\\\a_2=\frac{3}{2}+1\times \frac{5}{6}\\\\a_3=\frac{3}{2}+2\times \frac{5}{6}\\\\.\\.\\.\\a_n=\frac{3}{2}+(n-1)\times \frac{5}{6}\\\\S_n=a_1+a_2+a_3+......+a_n\\\\S_n=(\frac{3}{2}+0\times \frac{5}{6})+(\frac{3}{2}+1\times \frac{5}{6})+(\frac{3}{2}+2\times \frac{5}{6})+....+(\frac{3}{2}+[n-1]\times \frac{5}{6})\\\\S_n=\sum_{i=1}^n [\frac{3}{2}+(i-1)\times \frac{5}{6}]\\\\S_n=(\frac{3}{2}+\frac{3}{2}+\frac{3}{2}+...n\ times)+\frac{5}{6}(1+2+3+4+...+(n-1))\\\\$

$S_n=\frac{3}{2}\times n+\frac{5}{6}\times \frac{n(n-1)}{2}\\\\$

$S_{12}=\sum_{i=1}^{12} [\frac{3}{2}+(i-1)\times \frac{5}{6}]$

$S_{12}=\frac{3}{2}\times 12+\frac{5}{6}\times \frac{(12)(12-1)}{2}\\\\S_{12}=18+55\\\\S_{12}=73$

5 0

3 years ago