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Makovka662 [10]
3 years ago
12

30 POINTS!!!

Mathematics
1 answer:
Cloud [144]3 years ago
3 0

Answer:

A, C, & D

Step-by-step explanation:

A square root has the form \sqrt[2]{x}  = x^{1/2} and can be represented in exponential form. Let's convert all the expressions to \sqrt{x} this form. 4 square root 5 is 4\sqrt{25} =\sqrt{16*5}=\sqrt{80}

A. 2\sqrt{20} =\sqrt{4*20}=\sqrt{80}

B. 6^{1/2}-5^{1/2} =\sqrt{6}-\sqrt{5}

C. 3*5^{1/2}+5^{1/2} =3\sqrt{5}+\sqrt{5}=4\sqrt{5}=\sqrt{16*5}=\sqrt{80}

D. 4*5^{1/2}=4\sqrt{5}=\sqrt{16*5}=\sqrt{80}

E.2\sqrt{10} =\sqrt{4*10}=\sqrt{40}

F.  3*5^{1/2}=3\sqrt{5}=\sqrt{9*5}=\sqrt{45}

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Answer:

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Step-by-step explanation:

4 0
3 years ago
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Quiz 1
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Please help and show work!!
telo118 [61]

Let’s start by considering any 2 points falling on the line, the intercepts are the ones which come to my mind. Thus, the line 2x+3 will originally intersect the x- axis at (−32,0) and the y- axis at (0,3).

So, the basic insight is that on rotating the origin, the axes rotate. But the intercepts (their lengths) don’t change. The axis that is being intercepted will change, not the distance of intercepting points from the origin until our line is itself rotated. (Keep scribbling)

For the first case, we rotate the axes clockwise by a right angle. Now notice that the negative x-axis replaces the positive y-axis. So, our line now intercepts the negative x- axis at a distance 3 from the origin. Similarly, the negative y- axis replaces the negative x- axis. So, our line intersects the negative y- axis at distance 1.5 .

Therefore, the new intercepts are X(−3,0) and Y(0,−1.5). We can hence produce the new equation for our line in the slope- intercept form as

y=−x2−1.5 .

Similarly, you can imagine the other cases as axes rotation/replacement.

For 180∘, the equation would be y=2x−3 .

For 270∘, the equation would be y=−x2+1.5 .



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3 years ago
What is the slope of a line perpendicular to the line with the equation y = 6 x + 2
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