D=sqrt[(x1-x2)^2+(y2-y1)^2]
(0,10) x1=0 y1=10 and (-9,1) x2=-9 y2=1
now d=sqrt[(-9-0)^2+(1-10)^2]=12.72792206 units
Let the third side = x.
The sum of any two sides must be greater than the third side
14 + 9 > x
23 > x
14 + x > 9
x > -5
9 + x > 14
x > 5
So 5 < x < 23
Answer:
10
Step-by-step explanation:
We will use trigonometry to solve this problem.
We see that the side provided is the hypotenuse and the side we are looking for is opposite to the angle provided. Thus, we will use sin since sin uses opposite/hypotenuse.
Now we solve.
sin45 = x/14
sin45 * 14 = x
x = 9.899494936611665
Answer:
ZM = 8
WM = 12
XZ = 7
XN = 21
LZ = 20
Step-by-step explanation:
The centroid of a triangle is the point of intersection of the midpoint of the each of the three sides of a triangle. The centroid of a triangle is located inside the triangle and it is known as the center of gravity.
The centroid theorem for a triangle states that the centroid of a triangle is located at 2/3 of the distance from the vertex of the triangle of the middle of the opposite side.
ZM = (2/3)WM (centroid theorem)
Therefore: WZ = (1/3)WM
WM = 3WZ = 3 * 4 = 12
ZM = (2/3) * WM = 2/3 * 12 = 8
ZN = (2/3)XN (centroid theorem)
XN = (3/2)ZN = 3/2 * 14 = 21
XN = 21
XZ + ZN = XN
XZ + 14 = 21
XZ = 7
LZ = (2/3)LY (centroid theorem)
Therefore: ZY = (1/3)LY
LY = 3ZY = 3 * 10 = 30
LZ = (2/3) * LY = 2/3 * 30 = 20