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NeTakaya
3 years ago
14

It this right y=-5x+2 Please no files or links!

Mathematics
1 answer:
xeze [42]3 years ago
5 0

Answer:

I don't think so.

Step-by-step explanation:

Here, my own graph.

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What happens to the value of the expression <img src="https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7Bx%7D%20%2B5" id="TexFormula1" tit
Paraphin [41]

Answer:

A) increases

Step-by-step explanation:

5/x + 5

suppose x = 5; then 5/5 + 5 = 1 + 5 = 6

            x = 2; then    5/2 + 5 = 2.5 + 5 = 7.5

            x = 1 ;then 5/1 + 5 = 5 + 5 = 10

So when x value decreases from a large positive number to a small positive number, 5/x + 5 increases

3 0
3 years ago
Find the coordinates of the image after a reflection across the line y = x.
Marat540 [252]

Answer:

(2 1) for L (4 3) for G  (4 -1)

Step-by-step explanation:

5 0
3 years ago
X=4, y= -7, z=9 solve: -2x-3y+z
vesna_86 [32]

Answer:

22

Step-by-step explanation:

To solve this we can plug the values in.

-2x-3y+z

-2(4)-3(-7)+(9)

Simplify.

-8+21+9

Add.

22

8 0
3 years ago
If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid
Artist 52 [7]
Check the picture below.  Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm².  Also, recall, the base is a square, thus, length = width = x.

\bf \textit{volume of a rectangular prism}\\\\&#10;V=lwh\quad &#10;\begin{cases}&#10;l = length\\&#10;w=width\\&#10;h=height\\&#10;-----\\&#10;w=l=x&#10;\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\&#10;-------------------------------\\\\&#10;\textit{surface area}\\\\&#10;S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h&#10;\\\\\\&#10;\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\&#10;-------------------------------\\\\&#10;V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3

so.. that'd be the V(x) for such box, now, where is the maximum point at?

\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2&#10;\\\\\\&#10;\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100&#10;\\\\\\&#10;x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it.  Check the second picture below.

so, the volume will then be at   \bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3

6 0
3 years ago
What is the summation notation for the series? 200+175+150+125+___+(-300)
ozzi
  21
  E    (225-25n)
n=1
So its D.
5 0
3 years ago
Read 2 more answers
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