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Mariana [72]
3 years ago
14

Six less than seven times a number is equal to negative twenty.

Mathematics
2 answers:
Rainbow [258]3 years ago
7 0
Hope this helps with the answer to your question ;)

Nady [450]3 years ago
5 0

Answer:

x = -2

Step-by-step explanation:

6 is less than 7 times a no.S0,

Let the number be x.

7x-6= -20

7x= -20+6

7x= -14

x = -14/7

hence,x= -2

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Please help me on this question
Naily [24]
Hoi!

The converse of the Pythagorean Theorem states that <span>if the square of the length of the longest side of a triangle is equal to the sum of the squares of the other two sides, then the triangle is right.

To determine if this is a right triangle, let's figure out the values of each side.

√36 = 6
√18 = 4.2

Now we use the formula a² + b² = c² to determine if this is a right triangle.

4.2² + 4.2² = 6²

18 + 18 = 36

36 = 36

This triangle is a right triangle, so your answer is True.


</span>
6 0
3 years ago
Read 2 more answers
#83 will give brainliest with best response!​
Brilliant_brown [7]

Answer:

\frac{31x-159}{168y}

Step-by-step explanation:

\frac{x-4}{7y} - \frac{x+7}{8y} + \frac{x+3}{6y}

the LCD of the denominators is 168y , then

\frac{24(x-4)-21(x+7)+28(x+3)}{168y} ← distribute and simplify numerator

= \frac{24x-96-21y-147+28x+84}{168y}

= \frac{31x-159}{168y}

8 0
3 years ago
Read 2 more answers
Use lagrange multipliers to find the point on the plane x â 2y + 3z = 6 that is closest to the point (0, 2, 4).
Arisa [49]
The distance between a point (x,y,z) on the given plane and the point (0, 2, 4) is

\sqrt{f(x,y,z)}=\sqrt{x^2+(y-2)^2+(z-4)^2}

but since \sqrt{f(x,y,z)} and f(x,y,z) share critical points, we can instead consider the problem of optimizing f(x,y,z) subject to x-2y+3z=6.

The Lagrangian is

L(x,y,z,\lambda)=x^2+(y-2)^2+(z-4)^2+\lambda(x-2y+3z-6)

with partial derivatives (set equal to 0)

L_x=2x+\lambda=0\implies x=-\dfrac\lambda2
L_y=2(y-2)-2\lambda=0\implies y=2+\lambda
L_z=2(z-4)+3\lambda=0\implies z=4-\dfrac{3\lambda}2
L_\lambda=x-2y+3z-6=0\implies x-2y+3z=6

Solve for \lambda:

x-2y+3z=-\dfrac\lambda2-2(2+\lambda)+3\left(4-\dfrac{3\lambda}2\right)=6
\implies2=7\lambda\implies\lambda=\dfrac27

which gives the critical point

x=-\dfrac17,y=\dfrac{16}7,z=\dfrac{25}7

We can confirm that this is a minimum by checking the Hessian matrix of f(x,y,z):

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

\mathbf H is positive definite (we see its determinant and the determinants of its leading principal minors are positive), which indicates that there is a minimum at this critical point.

At this point, we get a distance from (0, 2, 4) of

\sqrt{f\left(-\dfrac17,\dfrac{16}7,\dfrac{25}7\right)}=\sqrt{\dfrac27}
8 0
3 years ago
If you earned up to $113,700 in 2013 from an employer, your social security tax rate was 6.2% of your income. If
dedylja [7]

Answer with Step-by-step explanation:

We are given that

If you earned upto $113,700 in 2013 from an employer then your security tax=6.2% of income

If you earned over $113,700 then, you paid amount of tax=$7049.40

We have to find the money you would have made when you paid $4000 in social security tax in 2013.

Let x be the income and f(x) be the amount of tax.

f(x)=\left\{\begin{matrix}0.062x&,if\ \ 0

Substitute the values then we get

4000=0.062x

x=\frac{4000}{0.062}=$64516.13

When you would have mad $64516.13 then you paid $4000 in social security tax in 2013.

7 0
3 years ago
DO NOT SKIP!! Let’s see who smart enough to work out both problems
gavmur [86]

Answer:

where are the 2 problems?

8 0
3 years ago
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