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Margaret [11]
4 years ago
9

Can someone help me understand about cross sections?

Mathematics
1 answer:
Musya8 [376]4 years ago
7 0
What are they? :<span>a surface or a type of shape that is or would be revealed or proven by making a straight cut through an object of some sort, especially at right angles to an axis.</span>
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Cuanto es r2-2r-7=0​
vekshin1

Answer:

Step-by-step explanation:

The solution is attached

6 0
3 years ago
Find the sum.<br> (X+3)+(2x-1)
leonid [27]

Answer:

3x+2

Step-by-step explanation:

x+3+2x−1

=x+3+2x+−1

Combine Like Terms:

=x+3+2x+−1

=(x+2x)+(3+−1)

=3x+2

Brainliest plz. If you want...

7 0
3 years ago
Solve for n.<br><br> -53 + n = -28
MrRa [10]
25 is the answer you do -28 - (-53) And you get 25 and then you plug your answer into n and you get your answer 

6 0
3 years ago
Read 2 more answers
Brian is drawing a scale diagram of a building. for every 10 m of the building he draws a line 5 cm long. Bryn thinks he is usin
ivann1987 [24]

Answer:

200:1, Bryn is correct.

Step-by-step explanation:

Each 10 m is represented by a 5cm length on the diagram.  We first note that 100 cm = 1 meter.   5 cm is (0.5 cm)*(1 meter/100 cm) =0.05 meters.

The 0.05 meters on the diagram represents 10 meters on the actual building.  The ratio is (10 meters/0.05 meters) or 200:1.  This is what Bryn believes is the ratio.  

7 0
2 years ago
One factor of x3 + 2x2 -x -2 is x+2 . Find two other factors of this polynomial.
SVEN [57.7K]

Answer:

x^3+2x^2-x-2=(x+2)(x-1)(x+1)

The other two factors are x-1 and x+1

Step-by-step explanation:

Use synthetic division:

x^3+2x^2-x-2 / x+2

-2 | 1 2 -1 -2

       -2 0 2

_________

     1 0 -1 0

This means x^2-1 with no remainder, but we can still break it down. The factors of -1 are 1 and -1, so we must find the factors:

1 | 1 0 -1

      1  1

______

   1  1 0

This means x+1 so that's one factor

-1 | 1 0 -1

      -1  1

_______

    1 -1 0

This means x-1 so that's the other factor

Thus, the factors of x^3+2x^2-x-2 are (x+2)(x+1)(x-1)

4 0
3 years ago
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