Question

If $y^2= 36$, what is the greatest possible value of $y^3$?

Answer 1

Answer:

The greatest possible value of $y^3=216$

Step-by-step explanation:

We have the statement $y^2=36$, and we have to find the greatest possible value of $y^3$, first we need to find the value of y.

$y^2=36$, to get the y by itself on the left side, we need to take the square root of both sides. $\sqrt{y^2} =\sqrt{36}$ The square root of $y^2$ is y, because y*y = $y^2$, and the square root of 36 is 6 or -6.

We now need to find the greatest value of $y^3$. When we plug in 6 to $y^3$, we get positive 216, and when we plug in -6, we get -216. We need to find the greatest possible value, so in this case we compare 216 and -216, 216 is greater than -216, so the answer would be positive 216.