180-132+x-6x+12=0
48+x-6x+12=0
48-5x+12=0
60-5x=0
-5x=-60
x=12
Answer:
Rain is correct, calculates correctly, 238.5 square inches
Step-by-step explanation:
The given triangular pyramid is shown with the dimensions.
The surface area of the triangular pyramid is given by :
![$A=\frac{1}{2}\left(a \times b\right) + 3\left(\frac{1}{2}\times b\times s\right)$](https://tex.z-dn.net/?f=%24A%3D%5Cfrac%7B1%7D%7B2%7D%5Cleft%28a%20%5Ctimes%20b%5Cright%29%20%2B%203%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%5Ctimes%20b%5Ctimes%20s%5Cright%29%24)
![$A=\frac{1}{2}\left(10 \times 8.7\right) + 3\left(\frac{1}{2}\times 10\times 13\right)$](https://tex.z-dn.net/?f=%24A%3D%5Cfrac%7B1%7D%7B2%7D%5Cleft%2810%20%5Ctimes%208.7%5Cright%29%20%2B%203%5Cleft%28%5Cfrac%7B1%7D%7B2%7D%5Ctimes%2010%5Ctimes%2013%5Cright%29%24)
![$A=43.5+(3\times 65)$](https://tex.z-dn.net/?f=%24A%3D43.5%2B%283%5Ctimes%2065%29%24)
![$A=43.5+195$](https://tex.z-dn.net/?f=%24A%3D43.5%2B195%24)
![$A=238.5 \ \text{inche}^2$](https://tex.z-dn.net/?f=%24A%3D238.5%20%5C%20%5Ctext%7Binche%7D%5E2%24)
Therefore, the surface area of the triangular pyramid is = 238.5 square inches.
If you'd graph this function, you'd see that it's positive on [-1.5,0], and that it's possible to inscribe 3 rectangles on the intervals [-1.5,-1), (-1,-0.5), (-0.5, 1].
The width of each rect. is 1/2.
The heights of the 3 inscribed rect. are {-2.25+6, -1+6, -.25+6} = {3.75,5,5.75}.
The areas of these 3 inscribed rect. are (1/2)*{3.75,5,5.75}, which come out to:
{1.875, 2.5, 2.875}
Add these three areas together; you sum will represent the approx. area under the given curve on the given interval: 1.875+2.5+2.875 = ?
Answer:
dy/dx=8
Step-by-step explanation:
note this differentiating a constant you get zero for that of a function like 8x you would use the index or power of x to multiply the coefficient of the x after substrate 1 from the power of the x putting that in writing for the above question we get
y'=dy/dx=(8*1)x^(1-1) - 0
y'=dy/dx=8x^0
y'=dy/dx=8
If u divide the area by length then u will get the width as x+4