Use
y
2
−
y
2
x
2
−
x
1
4
−
9
2
−
3
=
−
5
−
1
=
5
Answer link
Jim G.
Jun 11, 2018
y
=
5
x
−
6
Explanation:
the equation of a line in
slope-intercept form
is.
∙
x
y
=
m
x
+
b
where m is the slope and b the y-intercept
to calculate m use the
gradient formula
∙
x
m
=
y
2
−
y
1
x
2
−
x
1
let
(
x
1
,
y
1
)
=
(
2
,
4
)
and
(
x
2
,
y
2
)
=
(
3
,
9
)
m
=
9
−
4
3
−
2
=
5
1
=
5
y
=
5
x
+
b
←
is the partial equation
to find b substitute either of the 2 given points
into the partial equation
using
(
2
,
4
)
then
4
=
10
+
b
⇒
b
=
4
−
10
=
−
6
y
=
5
x
−
6
←
is the equation of lineAnswer:
Step-by-step explanation:
Use
y
2
−
y
2
x
2
−
x
1
4
−
9
2
−
3
=
−
5
−
1
=
5
Answer link
Jim G.
Jun 11, 2018
y
=
5
x
−
6
Explanation:
the equation of a line in
slope-intercept form
is.
∙
x
y
=
m
x
+
b
where m is the slope and b the y-intercept
to calculate m use the
gradient formula
∙
x
m
=
y
2
−
y
1
x
2
−
x
1
let
(
x
1
,
y
1
)
=
(
2
,
4
)
and
(
x
2
,
y
2
)
=
(
3
,
9
)
m
=
9
−
4
3
−
2
=
5
1
=
5
y
=
5
x
+
b
←
is the partial equation
to find b substitute either of the 2 given points
into the partial equation
using
(
2
,
4
)
then
4
=
10
+
b
⇒
b
=
4
−
10
=
−
6
y
=
5
x
−
6
←
is the equation of line
Answer:
The weight in ounces of one box = 15ounces
Step-by-step explanation:
We are told the relationship between the number of boxes and the weight of the crackers in the boxes is given as 11boxes and 165ounces respectively.
In order words, 11boxes weigh 165ounces.
To determine the weight, in ounces, of one box, we would divide the weight of the 11boxes by the number of boxes.
Weight of the 11boxes = 165ounces
Number of boxes that gives that weight = 11
The weight of one box = 165/11
The weight of one box = 15ounces
Answer:
4)..21 units
5). 15 units
6). 25 units
Step-by-step explanation:
4). Since ΔABC ~ ΔDEF,
Their corresponding sides will be proportional.
Since, 
x = 
x = 21 units
5). Since ΔABC ~ ΔDEF,
x = 15 units
6). Since ΔABC ~ ΔDEF,
x = 25 units
