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prohojiy [21]
3 years ago
6

5x - 15 = 20 The first step in solving this equation is to... subtract 15 from both sides of the equation. add 15 to both sides

of the equation. divide both sides of the equation by 5. add -20 to both sides of the equation.
Mathematics
1 answer:
OLga [1]3 years ago
3 0

Honestly the answer might be divide by 5. It may not be right tho. Sorry if It is wrong.


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Find a and b. Help me please.
Yakvenalex [24]
Hi there. Actually, the image that you have provided us with is a little bit blurry so, if you can make the image a little bit clearer, then I can help you with this question.
Thanks.
4 0
3 years ago
An envelope contains three cards: a black card that is black on both sides, a white card that is white on both sides, and a mixe
Over [174]

Answer:

There is a  2/3  probability that the other side is also black.

Step-by-step explanation:

Here let B1: Event of picking a card that has a black side

B2: Event of picking a card that has BOTH black side.

Now, by the CONDITIONAL PROBABILITY:

P(B_2/B_1 )  = \frac{P(B_1\cap B_2)}{P(B_1)}

Now, as EXACTLY ONE CARD has both sides BLACK in three cards.

⇒ P (B1 ∩ B2) = 1 /3

Also, Out if total 6 sides of cards, 3 are BLACK from one side.

⇒ P (B1 ) = 3 /6 = 1/2

Putting these values in the formula, we get:

P(B_2/B_1 )  = \frac{P(B_1\cap B_2)}{P(B_1)} = \frac{1}{3}  \times\frac{2}{1} = \frac{2}{3}

⇒ P (B2 / B1)  =  2/3

Hence, there is a  2/3  probability that the other side is also black.

 

5 0
3 years ago
Choose one question from the chart and complete it showing all steps. :)
OLEGan [10]

Answer:

Question 1

Volume of a cylinder = πr²h

r= radius h= height

diameter = 2*radius

diameter = 2* 4cm= 8cm

Volume = π × 4² × 11

= 553.14cm³

7 0
3 years ago
CHECK MY ANSWER??
Tatiana [17]
You are partially correct :) 2^SQR(10) x SQR(10) = 20 
The answer is just 20
4 0
3 years ago
In a baseball tournament, teams get 5 points for a win, 3 points for a tie and 1 point for a loss Nathan’s team has 29 points ho
puteri [66]

Answer:

37 different combinations

Step-by-step explanation:

First of all, we will count the possible combinations that add up to 29.

-Losses only;

One possibility: 29 losses

-Ties & losses;

Nine possibilities: 1 tie and 26 losses; 2 ties and 23 losses; 3 ties and 20 losses;4 ties and 17 losses; 5 ties and 14 losses; 6 ties and 11 losses; 7 ties and 8 losses; 8 ties and 5 losses; 9 ties and 2 losses

-Wins & losses

Five possibilities: 1 win and 24 losses; 2 wins and 19 losses; 3 wins and 14 losses; 4 wins and 9 losses; 5 wins and 4 losses

Now, what we want to find from the question is number of possibilities for wins, ties, and losses all together. So, we will count up the ties and losses in the remainder for each case of a given number of wins.

Thus;

For 0 Wins: 0 ties and 29 losses; 1 tie and 26 losses; 2 ties and 23 losses; 3 ties and 20 losses;4 ties and 17 losses; 5 ties and 14 losses; 6 ties and 11 losses; 7 ties and 8 losses; 8 ties and 5 losses; 9 ties and 2 losses.

Which sums up to 10 possibilities

For 1 win; 0 ties and 24 losses; 1 tie and 21 losses........8 ties and 0 losses.

Which sums up to 9 possibilities

For 2 wins; 0 ties and 19 losses; 1 tie & 16 losses............ 6 ties and 1 loss.

Which sums up to 7 possibilities

For 3 wins; 0 ties and 14 losses; 1 tie and 11 losses ....... 4 ties and 2 losses.

Which sums up to 5 possibilities

For 4 wins; 0 ties & 9 losses; 1 tie and 6 losses....... 3 ties and 0 losses

Which sums up to 4 possibilities

For 5 wins; 0 ties and 4 losses; 1 tie and 1 loss

Which sums up to 2 possibilities

Thus;

Total number of possibilities of combinations of wins, ties and losses = 10 + 9 + 7 + 5 + 4 + 2 = 37

8 0
3 years ago
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