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3 years ago

Negative symbol as opposite | HELP PLS

Mathematics

2 answers:

nordsb [41]3 years ago

5 0

Negative of 0 is just 0

Hope this helps :)

Pepsi [2]3 years ago

4 0

Answer: I would have to say its zero

Sorry if I got it wrong

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The sum of four consecutive odd integers is three more than five times the least of the integers. Find the integers.

Olegator [25]

Answer:

Step-by-step explanation:

{k - some integer}

2k+1 - the first odd integer (the least)

5(2k+1) - five times the least

5(2k+1)+3 -<u> three more than five times the least</u>

2k+1+2 = 2k+3 - the odd integer consecutive to 2k+1

2k+3+2 = 2k+5 - the next odd consecutive integer (third)

2k+5+2 = 2k+7 - the last odd consecutive integer (fourth)

2k+1+2k+3+2k+5+2k+7 - <u>the sum of four odd consecutive integers</u>

2k+1 + 2k+3 + 2k+5 + 2k+7 = 5(2k+1) + 3

8k + 16 = 10k + 5 + 3

- 10k -10k

-2k + 16 = 8

-16 - 16

-2k = -8

÷(-2) ÷(-2)

k = 4

2k+1 = 2•4+1 = 9

2k+3 = 2•4+3 = 11

2k+5 = 2•4+5 = 13

2k+7 = 2•4+7 = 15

Check: 9+11+13+15 = 48; 48-3 = 45; 45:5 = 9 = 2k+1

4 0

3 years ago

Juan’s purchase before sales tax was added totaled $46.00. the total including tax was $48.76. what was the sales tax rate?

Klio2033 [76]

The sales tax rate is 6%.

4 0

3 years ago

Read 2 more answers

D.sqrt(2+x^/2)<br> Solve this question please

lidiya [134]

Answer:

Option a.

Step-by-step explanation:

By looking at the options, we can assume that the function y(x) is something like:

$y = \sqrt{4 + a*x^2}$

$y' = (1/2)*\frac{1}{\sqrt{4 + a*x^2} }*(2*a*x) = \frac{a*x}{\sqrt{4 + a*x^2} }$

such that, y(0) = √4 = 2, as expected.

Now, we want to have:

$y' = \frac{x*y}{2 + x^2}$

replacing y' and y we get:

$\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}$

Now we can try to solve this for "a".

$\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}$

If we multiply both sides by y(x), we get:

$\frac{a*x}{\sqrt{4 + a*x^2} }*\sqrt{4 + a*x^2} = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}*\sqrt{4 + a*x^2}$

$a*x = \frac{x*(4 + a*x^2)}{2 + x^2}$

We can remove the x factor in both numerators if we divide both sides by x, so we get:

$a = \frac{4 + a*x^2}{2 + x^2}$

Now we just need to isolate "a"

$a*(2 + x^2) = 4 + a*x^2$

$2*a + a*x^2 = 4 + a*x^2$

Now we can subtract a*x^2 in both sides to get:

$2*a = 4\\a = 4/2 = 2$

Then the solution is:

$y = \sqrt{4 + 2*x^2}$

The correct option is option a.

7 0

3 years ago

Arthur earned 136$ in three weeks. He goes back to school in one more week. He needs at least 189$ to buy the new coat they he w

saul85 [17]

Answer:

189 minus 136 equals 53 so the answer is 53 dollars

3 0

3 years ago

In geometry, you can use deductive rules to

lana [24]

The answer is d
prove conjectures

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3 years ago