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Natalka [10]
2 years ago
8

Negative symbol as opposite | HELP PLS

Mathematics
2 answers:
nordsb [41]2 years ago
5 0
Negative of 0 is just 0

Hope this helps :)
Pepsi [2]2 years ago
4 0

Answer: I would have to say its zero

Sorry if I got it wrong

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11x - ? = 19x what is the missing number?
Verdich [7]

Answer:

8x !

Step-by-step explanation:

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2 years ago
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Suppose we take two different random samples from the same population of test scores. The population mean and standard deviation
Leto [7]

Answer:

The 95% confidence interval obtained with a sample size of 64 will give greater precision.            

Step-by-step explanation:

We are given the following in the question:

A 95% confidence interval is calculated with the following sample sizes

n_1 = 25\\n_2 = 64

The population mean and standard deviation are unknown.

Effect of sample size on confidence interval:

  • As the sample size increases the margin of error decreases.
  • As the margin of error decreases the width of the confidence level decreases.
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If we want a confidence interval with greater precision that is smaller width, we have to choose the higher sample size.

Thus, the 95% confidence interval obtained with a sample size of 64 will give greater precision.

3 0
3 years ago
Two identical square pyramids were joined at their bases to form the composite figure below.
gulaghasi [49]
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3 0
3 years ago
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How do you do this question?
erik [133]

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Use the first fundamental theorem of calculus.

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5 0
3 years ago
What are the coordinates of the point on the directed line segment from (-6, -3) to
melamori03 [73]

Given:

A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5.

To find:

The coordinates of that point.

Solution:

Section formula: If point divides a line segment in m:n, then the coordinates of that point are

Point=\left(\dfrac{mx_2+nx_1}{m+n},\dfrac{my_2+ny_1}{m+n}\right)

A point divides a directed line segment from (-6, -3) to (5,8) into a ratio of 6 to 5. Using section formula, we get

Point=\left(\dfrac{6(5)+5(-6)}{6+5},\dfrac{6(8)+5(-3)}{6+5}\right)

Point=\left(\dfrac{30-30}{11},\dfrac{48-15}{11}\right)

Point=\left(\dfrac{0}{11},\dfrac{33}{11}\right)

Point=\left(0,3\right)

Therefore, the coordinates of the required point are (0,3).

3 0
3 years ago
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