The probability of getting two good coils when two coils are randomly selected if the first selection is replaced before the second is made is 0.7744

Solution:

Total number of coils = number of good coils + defective coils = 88 + 12 = 100

p(getting two good coils for two selection) = p( getting 2 good coils for first selection ) $\times$ p(getting 2 good coils for second selection)

p(first selection) = p(second selection) = $\frac{\text { number of good coils }}{\text { total number of coils }}$

Hence, p(getting 2 good coil for two selection) = $\frac{88}{100} \times \frac{88}{100} =\bold{0.7744}$

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3 years ago

What is the answer to - 1/3 (x+6)=0

Sauron [17]

$(-\frac{1}{3})(x+6)=0\\\\\frac{1}{3}(x+6)*3=0*3\\\\-1(x+6)=0\\\\-(x+6)*-1=0*-1\\\\x+6=0\\\\x=-6$

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Why is 2 the only even prime number

Temka [501]

Answer:

A prime number is a whole number greater than 1 whose only factors are 1 and itself

two is the only even prime number because it is divisible by only two and one. All the other even numbers are not prime because they are all divisible by two.

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Follow nikespear37 tik tok

hjlf

Answer:

no >:)

Step-by-step explanation:

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