I cant see ur attached thing
Make one of the variables drop out.
I'd go for the y since it's easiest in this problem.
Time the top equation by -1.
This changes the system to:
Add the equations.
The equation would be:
Or simply:
Solve for x by dividing.
Then, plug x into one of the original equations to find y.
I'm going to use the first one since the numbers are smaller, but you CAN use either.
Put these into an ordered pair.
(0,1)
That is your answer.
Hope this helped!
:)
The dimensions that would result to maximum area will be found as follows:
let the length be x, the width will be 32-x
thus the area will be given by:
P(x)=x(32-x)=32x-x²
At maximum area:
dP'(x)=0
from the expression:
P'(x)=32-2x=0
solving for x
32=2x
x=16 inches
thus the dimensions that will result in maximum are is length=16 inches and width=16 inches
Answer:
a: 0.08, or 8% chance he wins all 3
b: 0.42, or 42% chance he wins 2
Step-by-step explanation:
P(win A) = 0.8
P(lose A) = 0.2
P(win B) = 0.5
P(lose B) = 0.5
P(win C) = 0.2
P(lose C) = 0.8
The situations are independent, so we multiply probabilities together.
To win all 3: P(win A)*P(win B)*P(win C) = 0.8*0.5*.02 = 0.08
To win 2 of the 3 there are 3 ways to do this. We add up the probabilities of the 3 situations...
P(win A)*P(win B)*(lose C) = 0.8*0.5*0.8 = 0.32
P(win A)*P(lose B)*P(win C) = 0.8*0.5*0.2 = 0.08
P(lose A)*P(win B)*P(win C) = 0.2*0.5*.02 = 0.02
0.32 + 0.08 + 0.02 = 0.42
<em>Product hints at multiplication so -5n is AT LEAST meaning that it is at or greater than 35....</em>
<em />
-5n ≥ 35