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3 years ago

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Line AB passes through A(-3, 0) and B(-6, 5). What is the equation of the line that passes through the origin and is parallel to

Line AB?
A. 5x − 3y = 0
B. -x + 3y = 0
C. -5x − 3y = 0
D. 3x + 5y = 0
E. -3x + 5y = 0

1 answer:

MArishka [77]3 years ago

4 0

I hope this helps you

slope = 5-0/-6-(-3)= -5/3

(0,0)

m.(x1-x)=y1-y

-5/3.(0-x)=0-y

5x= -3y

5x+3y=0

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Step-by-step explanation:

we know that

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$\huge \boxed{\mathfrak{Question} \downarrow}$

Solve the following using Substitution method

2x – 5y = -13

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$\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}$

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Divide both sides by 2.

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Divide both sides of the equation by 23/2, which is the same as multiplying both sides by the reciprocal of the fraction.

$\large \underline{ \underline{ \sf \: y=3 }}$

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$\huge\boxed{ \boxed{\bf \: x=1, \: y=3 }}$

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