5q ≥ 8q - 3/2
<em><u>Add 3/2 to both sides.</u></em>
3/2 + 5q ≥ 8q
<em><u>Subtract 5q from both sides.</u></em>
3/2 ≥ 3q
<em><u>Multiply both sides by 2.</u></em>
3 ≥ 6q
<em><u>Divide both sides by 6.</u></em>
0.5 ≥ q.
The value of q is less than or equal to 0.5.
Answer: The second one
Step-by-step explanation:
response/25=x/100 and then you solve for x
Answer:
24x^2
Step-by-step explanation:
When expanded (x+2)^4= x^4+8x^3+24x^2+32x+16
The only term that matches with these is 24x^2
Answer:
a) -2 and 4
b) function 2
Step-by-step explanation:
a)
rate of change is rise over run: change in y / change in x.
function 1:
- i will use first 2 pairs of data
- change in y: 5 - 3 = 2
- change in x: -2 - (-1) = -1
-rate of change = 2/-1 = -2
function 2:
- same idea, but find two points on the graph!
- (0,4) and (-1,0) for example! pick easy points
- change in y is 4. chabge in x is 1
- rate of change is 4
b)
function b has greatest rate of change. 4 > -2
Answer:
The original price is $650
Step-by-step explanation:
There's an actual algebra method for this, but this is my method because I find it way easier to remember.
Since the most you can discount out of an item is 100% (well, it's considered free then) let's subtract 100 - 34, which is 66.
Now, turn it into a decimal because it makes the numbers easier- 0.66.
Since when you're finding the discount of an original price, you multiply the original price by the discount- instead for finding the original price for a discounted item we divide $429 by 0.66 instead, since when you divide a number by another number that's under 1 the quotient is a larger number.
So, 429 ÷ 0.66 = 650.
Therefore, the original price of the $429 sale price for a 34% discount is $650.
