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Kay [80]
4 years ago
9

1 over 5 plus 2 over 5

Mathematics
1 answer:
g100num [7]4 years ago
8 0

Answer:

\frac{3}{5}

Step-by-step explanation:

Before you add 2 fractions, the denominator needs to be the same. If they are the same, which they are, then add the 2 numerators.

1 plus 2 equals 3.

So the answer is 3 over 5.

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Each square on the grid represents 1 m2. What is the approximate area of this grassy field?
Rudik [331]
The answer is B estimated number is 20
8 0
3 years ago
Read 2 more answers
Jill weighs 120 pounds and is gaining ten pounds each month. Paris weighs 150 pounds and is gaining 4 pounds each month. How man
lyudmila [28]

Answer:

5 months

Step-by-step explanation:

To solve this problem, we need to create and algebraic equation for when Jill's weight will be equal to Paris's. If we take their current weight and then add the additional weight gain per month times the number of months, we can calculate the amount of time it will take for their weight to be equal by solving for m.

120+10m=150+4m\\10m-4m=150-120\\6m=30\\m=5

8 0
3 years ago
How many solutions does the following equation have?<br><br> 0 = -6|9v - 7|
Lunna [17]

Answer: One solution

Step-by-step explanation:

V=7/9

6 0
3 years ago
F(x) = -3(x - 1)2 + 3<br> How do you turn it into standard form
Zepler [3.9K]

Answer:

\displaystyle \boxed{f(x) = 6x - 3x^2}

Step-by-step explanation:

f(x) = −3(x² - 2x + 1) + 3

f(x) = −3x² + 6x - 3 + 3

f(x) = −3x² + 6x

** The above answer is written in reverse, which is the exact same result.

I am joyous to assist you anytime.

7 0
4 years ago
A poll found that 53% of a sample of 1170 teens in a certain large country go online several times a day. (Treat this sample as
posledela

Answer:(a) margin error = 2.4%

(b) The margin error gives the measure in percentage of how the population parameter determined differ from the real population statistics or value.

(c) in 90% of the samples of teens in the country, the percent who go online several times a day will be within 50.6% and 55.4%. of the estimated 100%

Step-by-step explanation:

Using the proportion formulae

Margin error = z √p(1-p)/n

n= 1170, p = 53% = 0.53, 1-p = 0.47

and the z value at 90% C.I = 1.645

M error= 1.645 √0.53×0.47/1170

Margin error = 0.024 = 0.024 ×100

Margin error = 2.4%

53 - 2.4 = 50.6% and 53 + 2.4 = 55.4%

In other words 90% of the time: the number of teens who go online several time a day will be between 50.6 and 55.4%.

8 0
3 years ago
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