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VLD [36.1K]
3 years ago
5

Find the surface area of the regular pyramid. Write your answer as a decimal. (solved)

Mathematics
1 answer:
lisov135 [29]3 years ago
3 0

Answer:

The total surface area is 145.12 sq.m.

Step-by-step explanation:

We are supposed to find the surface area of given figure

Length of rectangular part = 15 m

Breadth of rectangular part = 8 m

Area of rectangular part =Length \times Breadth = 15 \times 8 = 120 sq.m.

Diameter of semi circle = 8 m

Radius of semicircle = \frac{8}{2}=4 m

Area of semicircle = \frac{\pi r^2 }{2}=\frac{3.14 \times 4^2}{2}=25.12 sq.m.

Total surface area = 120+25.12=145.12 sq.m.

Hence The total surface area is 145.12 sq.m.

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3 years ago
Given f(x), find g(x) and h(x) such that f(x)=g(h(x)) and neither g(x) nor h(x) is solely x. f(x)=−3x+4⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯⎯√3+5
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Answer:

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Step-by-step explanation:

Consider the given function is

f(x)=\sqrt[3]{-2x+4}-5

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f(x)=\sqrt[3]{(-2x+4)}-5

Let h(x)=-2x+4, then we get

f(x)=g(h(x))=\sqrt[3]{h(x)}-5

Substitute h(x)=x in the above function.

g(x)=\sqrt[3]{x}-5

Therefore, the required functions are h(x)=-2x+4 and g(x)=\sqrt[3]{x}-5.

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g(h(x))=g(-2x+4)             [\because h(x)=-2x+4]

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g(h(x))=f(x)

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