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White raven [17]
4 years ago
14

Simplify 64/100 please

Mathematics
1 answer:
Umnica [9.8K]4 years ago
6 0
64/100 = 32/50 = 16/25

Trick: try dividing by 2 and continue
until you find the lowest terms.
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Stitu wants to cut square pieces of chart paper which is 48 cm long and 32 cm wide .If she is able to get 6 equal pieces ,then f
alisha [4.7K]

Answer:

Length of each piece = 16cm.

Step-by-step explanation:

Since the chart paper is 48cm x 32cm in size, finding the total area of the paper would be A = l x w, where l=length of the paper and w=width.

A = 48 x 32 = 1536cm²

Since Stitu was able to get 6 equal pieces, then we can take the total area and divede by 6:

\frac{1536}{6} = 256

Since 256cm² represents the area of each square, we can take the square root of this number to find the length of just one square since the formula for the area of a square is A=s², where s=the length of one side:

s² = 256 so √s² = √256 or s = 16cm

8 0
3 years ago
Which graph represents the function described in the table?
Andru [333]

Answer:

where is the graph?

Step-by-step explanation:

6 0
3 years ago
A faucet leaks water at a constant rate of quart every 15 minutes.
OLga [1]

An hour is 60 minutes.

60 minutes/ 15 minutes = 4

There are 4 15 minute segments in an hour.

1 quart x 4 = 4 quarts per hour.

8 0
3 years ago
Read 2 more answers
A recipe for 1
Kazeer [188]

Answer:

A recipe for 1 pizza crust calls for 3/8 table spoon

therefore,

3 pizza crust calls =3/8 × 3=9/8=1.13

tablespoon .

Step-by-step explanation:

8 0
3 years ago
Compute the standard error for sample proportions from a population with proportion p= 0.55 for sample sizes of n=30, n=100 and
Pani-rosa [81]

Given Information:

Population proportion = p =  0.55

Sample size 1 = n₁ = 30

Sample size 2 = n₂ = 100

Sample size 3 = n₃ = 1000

Required Information:

Standard error = σ = ?

Answer:

$ \sigma_1 = 0.091 $

$ \sigma_2 = 0.050 $

$ \sigma_3 = 0.016 $

Step-by-step explanation:

The standard error for sample proportions from a population is given by

$ \sigma =  \sqrt{\frac{p(1-p)}{n} } $  

Where p is the population proportion and n is the sample size.

For sample size n₁ = 30

$ \sigma_1 =  \sqrt{\frac{p(1-p)}{n_1} } $

$ \sigma_1 =  \sqrt{\frac{0.55(1-0.55)}{30} } $

$ \sigma_1 = 0.091 $

For sample size n₂ = 100

$ \sigma_2 =  \sqrt{\frac{p(1-p)}{n_2} } $

$ \sigma_2 =  \sqrt{\frac{0.55(1-0.55)}{100} } $

$ \sigma_2 = 0.050 $

For sample size n₃ = 1000

$ \sigma_3 =  \sqrt{\frac{p(1-p)}{n_3} } $

$ \sigma_3 =  \sqrt{\frac{0.55(1-0.55)}{1000} } $

$ \sigma_3 = 0.016 $

As you can notice, the standard error decreases as the sample size increases.

Therefore, the greater the sample size lesser will be the standard error.

8 0
4 years ago
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