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lapo4ka [179]
3 years ago
12

If h(x) = (fºg)(x) and h(x) = 3(x+2)^2 find one possibility for f (x) and g(x).

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0

Answer:

f(x) = 3x^2

g(x) = x + 2

Step-by-step explanation:

Given

h(x) = 3(x+2)^2

h(x) = (fog)(x)

Required

Find  f(x) and g(x)

h(x) = (fog)(x)

Rewrite h(x)

h(x) = f(g(x))

If  h(x) = 3(x+2)^2

then

f(g(x)) = 3(x+2)^2

This implies that; the expression in the brackets are equal;

In other words; function g(x) on the left hand side is equal to expression x + 2 on the right hand side

So;

g(x) = x + 2

To find f(x), substitute g(x) with x

f(x) = 3(x)^2

f(x) = 3x^2

Final solutions are

f(x) = 3x^2

g(x) = x + 2

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Please help me with 1-4. I will give an Brainly and a bunch of extra points.
xz_007 [3.2K]

Answer:

\sf 1) \quad \sf A \cup C = \{a, b, c, d, e\}

\sf 2) \quad B \cap A = \{a, b, d\}

\sf 3) \quad B' = \{c, f, g, h \}

\sf 4) \quad A -(B \cap C') = \{a, c \}

Step-by-step explanation:

<u>Set Notation</u>

\begin{array}{|c|c|l|} \cline{1-3} \sf Symbol & \sf N\:\!ame & \sf Meaning \\\cline{1-3} \{ \: \} & \sf Set & \sf A\:collection\:of\:elements\\\cline{1-3} \cup & \sf Union & \sf A \cup B=elements\:in\:A\:or\:B\:(or\:both)}\\\cline{1-3} \cap & \sf Intersection & \sf A \cap B=elements\: in \:both\: A \:and \:B} \\\cline{1-3} \sf ' \:or\: ^c & \sf Complement & \sf A'=elements\: not\: in\: A \\\cline{1-3} \sf - & \sf Difference & \sf A-B=elements \:in \:A \:but\: not\: in \:B}\\\cline{1-3} \end{array}

Given sets:

  • U = {a, b, c, d, e, f, g, h}
  • A = {a, b, c, d}
  • B = {b, e, a, d}
  • C = {a, e}

Therefore:

  • Universal set = {a, b, c, d, e, f, g, h}
  • B' = not in B = {c, f, g, h}
  • C' = not in C = {b, c, d, f, g, h}

<u>Question 1</u>

\begin{aligned}\sf A \cup C & = \sf \{a, b, c, d\} \cup \{a,e\}\\& = \sf \{a, b, c, d, e\}\end{aligned}

<u>Question 2</u>

\begin{aligned}\sf B \cap A & = \sf \{b, e, a, d\} \cap \{a, b, c, d\}\\& = \sf \{a, b, d\}\end{aligned}

<u>Question 3</u>

\begin{aligned}\sf B' & = \rm U - \sf B\\& = \sf \{a, b, c, d, e, f, g, h \}-\{b, e, a, d\}\\& = \sf \{c, f, g, h \}\end{aligned}

<u>Question 4</u>

\begin{aligned}\sf A -(B \cap C') & = \sf \{a, b, c, d \}- \left( \{b, e, a, d \} \cap \{b, c, d, f, g, h \} \right)\\& = \sf \{a, b, c, d \}- \{b, d \} \\& = \sf \{a, c \}\end{aligned}

Learn more about set notation here:

brainly.com/question/28353607

3 0
2 years ago
Read 2 more answers
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