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3 years ago

Verify inverse functions

Mathematics

1 answer:

ziro4ka [17]3 years ago

4 0

Answer:

Step-by-step explanation:

Hello

(fog)(x)=f(g(x))=10(x-6)/10+6=x-6+6=x

(gof)(x)=(10x-6+6)/10=10x/10=x

So YES the functions are inverse

hope this helps

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Determine the x- and y- intercepts for the graph defined by the given equation.

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A container of orange juice has a pH of 3.3. Find the concentration of hydronium ions in the milk.

kap26 [50]

The concentration of the hydronium ions in the milk is 5.011×10⁻⁴ if the container of orange juice has a pH of 3.3.

<h3>What is pH value?</h3>

The pH of a solution is a measurement of the concentration of hydrogen ions in the solution, as well as its acidity or alkalinity. Normally, the pH scale ranges from 0 to 14.

We have:

A container of orange juice has a pH of 3.3.

The pH value = 3.3

$\rm pH = -log[H_3O^+]$

$\rm 3.3 = -log[H_3O^+]$

Removing log:

$\rm 10^{-3.3}=[H_3O^+]$

$\rm [H_3O^+] = 5.011\times10^{-4}$

Thus, the concentration of the hydronium ions in the milk is 5.011×10⁻⁴ if the container of orange juice has a pH of 3.3.

Learn more about the pH value here:

brainly.com/question/1503669

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2 years ago

Use the Quotient Property to Simplify Square Roots Number 129

Inessa05 [86]

Using the quotient property we would have

$\begin{gathered} \sqrt{\frac{75r^9}{8^8}}=\frac{\sqrt{75r^9}}{\sqrt{8^8}} \\ \end{gathered}$

This follows the rule

$\sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}$

From the simplified expression as shown above

$\frac{\sqrt{75r^9}}{\sqrt{8^8}}=\frac{\sqrt{3\times25\times r^9}}{\sqrt{(2^3)^8}}$

Thus;

$\frac{\sqrt{3\times25r^9}}{\sqrt{(2^3)^8}}=\frac{\sqrt{25}\times\sqrt{3}\times\sqrt{r^9}}{\sqrt{2^{^3\times8}}}=\frac{5\sqrt{3r^9}}{\sqrt{2^{24}}}$

Therefore

$\begin{gathered} Using\text{ fraction index law we could simplify the denominator} \\ \frac{5\sqrt{3r^9}}{2^{\frac{24}{2}}}=\frac{5\sqrt{3r^9}}{2^{12}} \end{gathered}$

We can not simplify the 3 and the r raised to power of 9 as their power is not even, hence the final answer is given below

$\frac{5\sqrt{3r^9}}{2^{12}}=\frac{5\sqrt{3r^9}}{4096}$

The final answer is :

$\frac{5\sqrt{3r^9}}{4096}$

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1 year ago