Answer:
15°
Step-by-step explanation:
Since P is on the median of ΔABC, it is equidistant from points B and C as well as from C and Q. Thus, points B, C, and Q all lie on a circle centered at P. (See the attached diagram.)
The base angles (B and C) of triangle ABC are (180° -30°)/2 = 75°. This means arc QC of the circle centered at P has measure 150°. The diameter of circle P that includes point Q is defined to intersect circle P at R.
Central angle RPC is the difference between arcs QR and QC, so is 180° -150° = 30°. Inscribed angle RQC has half that measure, so is 15°. Angle PQC has the same measure as angle RQC, so is 15°.
Angle PQC is 15°.
Answer:
<h3>$ 20 </h3>
Step-by-step explanation:
<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em>
<em>Can</em><em> </em><em>I</em><em> </em><em>have</em><em> </em><em>the</em><em> </em><em>brainliest</em><em> </em><em>please</em><em>?</em>
<em>Have</em><em> </em><em>a</em><em> </em><em>nice</em><em> </em><em>day</em><em>!</em>
The given complex number is ⇒ z = a + b i
The absolute value of z = √( a² + b² ) = 3.28
So, we will check which of the options will give 3.28
<span>( A) IF ⇒⇒ a=1.5 and b=1.7
</span>
<span>∴ √( a² + b² ) = √( 1.5² + 1.7²) = √5.14 ≈ 2.27
</span>
===================================
<span>(B) IF ⇒⇒ a=1.5 and b=3.3
</span>
<span>∴ √( a² + b² ) = √(1.5² + 3.3²) = √13.14 ≈ 3.62
</span>
====================================
<span>(C) IF ⇒⇒ a=1.7 and b=2.8
</span>
<span>∴ √( a² + b² ) = √(1.7² + 2.8²) = √10.73 ≈ 3.28
</span>
====================================
<span>(D) IF ⇒⇒ a=2.8 and b=3.3
</span>
∴ √( a² + b² ) = √(2.8² + 3.3²) = √18.73 ≈ 4.33
=====================================
So, the correct answer is option (C) <span>a=1.7,b=2.8</span>
Answer:
Length of sides of poster = 2 Ft
Length of sides of box = 2.41 Ft
Since the box has a longer side than the poster, the poster will lie flat when placed in the box.
Step-by-step explanation:
In order to determine if the poster will lie flat in the box or not, we will determine the length of the sides of the poster and the box, if the length of the side of the square poster is smaller than that of the box, it will lie flat. This is calculated as follows:
Area of poster = 4 square feet
Area of poster = (Length)²
4 = (Length)²
∴ Length = √(4)
Length of poster = 2 Ft
Volume of box = 14 cubic feet
Volume of box = (Length)³
14 = (Length)³
∴ Length = ∛(14)
Length = 2.41 Ft
∴ Length of sides of poster = 2 Ft
Length of sides of box = 2.41 Ft
Since the box has a longer side than the poster, the poster will lie flat when placed in the box.
32.92 next is 27 last is 230
