1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rudiy27
3 years ago
14

A national park has eighty thousand, nine-hundred twenty-three and eighty-six hundredths acres of land. Write in standard form

Mathematics
1 answer:
Tema [17]3 years ago
7 0

Hi :)

Eighty thousand nine hundred twenty three and eighty six hundredths

80,923.86

You might be interested in
Help me!!!!!!!!!???!!!!!!!!!!!!!!;
frozen [14]
20,112.5 meters

Multiply the length of the track by 10, then multiply that number by 5
3 0
3 years ago
Hey Algebra 1 Answer Key with notes.pdf go on that and there are the anwers and the answer key :)
Savatey [412]

Answer:

Ahh... Tsym for that. But what is the link of that website.

Step-by-step explanation:

Please give me brainliest :)

4 0
3 years ago
Solve for x <img src="https://tex.z-dn.net/?f=%20S%3D7%20x%5E%7B2%7D%20" id="TexFormula1" title=" S=7 x^{2} " alt=" S=7 x^{2} "
il63 [147K]
S = 7x^2....divide both sides by 7
1/7s (same as s/7) = x^2...now take sqrt of both sides
(+ - ) sqrt 1/7s = x
3 0
4 years ago
The open intervals on which f is concave upward. (enter your answer using interval notation.
N76 [4]
Khan academy has a lot on this sorry I couldn't answer bro
6 0
3 years ago
The amount of warpage in a type of wafer used in the manufacture of integrated circuits has mean 1.3 mm and standard deviation 0
valina [46]

Answer:

a) P(\bar X >1.305)=P(Z>\frac{1.305-1.3}{\frac{0.1}{\sqrt{200}}}=0.707)

And using the complement rule, a calculator, excel or the normal standard table we have that:

P(Z>0.707)=1-P(Z

b) z=-0.674

And if we solve for a we got

a=1.3 -0.674* \frac{0.1}{\sqrt{200}}=

So the value of height that separates the bottom 95% of data from the top 5% is 1.295.

c) P( \bar X >1.305) = 0.05  

We can use the z score formula:

P( \bar X >1.305) = 1-P(\bar X

Then we have this:

P(z< \frac{1.305-1.3}{\frac{0.1}{\sqrt{n}}}) = 0.95

And a value that accumulates 0.95 of the area on the normal distribution z = 1.64 and we can solve for n like this:

n = (1.64*\frac{0.1}{1.305-1.3})^2= 1075.84 \approx 1076

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

Let X the random variable that represent the amount of warpage of a population and we know

Where \mu=1.3 and \sigma=0.1

Since the sample size is large enough we can use the central limit theorem andwe know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

We can find the probability required like this:

P(\bar X >1.305)=P(Z>\frac{1.305-1.3}{\frac{0.1}{\sqrt{200}}}=0.707)

And using the complement rule, a calculator, excel or the normal standard table we have that:

P(Z>0.707)=1-P(Z

Part b

For this part we want to find a value a, such that we satisfy this condition:

P(\bar X>a)=0.75   (a)

P(\bar X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.25 of the area on the left and 0.75 of the area on the right it's z=-0.674. On this case P(Z<-0.674)=0.25 and P(z>-0.674)=0.75

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.674

And if we solve for a we got

a=1.3 -0.674* \frac{0.1}{\sqrt{200}}=

So the value of height that separates the bottom 95% of data from the top 5% is 1.295.

Part c

For this case we want this condition:

P( \bar X >1.305) = 0.05  

We can use the z score formula:

P( \bar X >1.305) = 1-P(\bar X

Then we have this:

P(z< \frac{1.305-1.3}{\frac{0.1}{\sqrt{n}}}) = 0.95

And a value that accumulates 0.95 of the area on the normal distribution z = 1.64 and we can solve for n like this:

n = (1.64*\frac{0.1}{1.305-1.3})^2= 1075.84 \approx 1076

6 0
3 years ago
Other questions:
  • Translate the phrase into a math expression.
    7·1 answer
  • © Make x the subject of the formula<br> – 62<br> a<br> 2c
    7·1 answer
  • HELP ME PLEASE ASAP?!?!<br> Which of the following is most likely the next step in the series?
    10·2 answers
  • For a Biology assignment, Lisa collected data on plant growth of a sunflower every week for 9 weeks. When Lisa first planted the
    8·1 answer
  • That is not right.6868
    5·1 answer
  • Misty correctly determined the equation of the linear function represented by the table of values below to be y = negative 2 x +
    15·2 answers
  • Diana is planting a garden in the shape of the sector below. What is the length of fencing needed for the curred part of the gar
    12·1 answer
  • Jenna is buying 6 new shirts at $18 each. Which of the following is NOT a way to write a calculation for how much money Jenna is
    6·1 answer
  • John can ride his bicycle at a rate of 14 miles per hour. Convert this rate to feet per second_
    13·1 answer
  • Just the bottom 2 please
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!