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3 years ago

CAN SOMEONE PLEASEEEE ANSERR THISSSSSSSS THANK YOU SO VERY MUCH

Mathematics

2 answers:

Lana71 [14]3 years ago

7 0

Use Pythagorean theorem.

Let x be the side we are looking to determine:

$x = \sqrt{20^2-8^2}=\sqrt{336}\approx 18.3$

the missing measure is approximately 18.3 units

Lapatulllka [165]3 years ago

6 0

Pyth. theorem
$\sqrt{20 { }^{2} - 8 {}^{2} }$

=18.33
=18.3 (corr. to the nearest tenth)

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If isme estimated that there are 50 students in the seventh grade class but there are actually 40 what is isme’s percent error?

Temka [501]

The percent error is 25 %

Solution:

Given that it is estimated that there are 50 students in the seventh grade class, but there are actually 40

To find: percent error

Percent error is the difference between a measured and known value, divided by the known value, multiplied by 100%

The formula for percent error is given as:

$\text{ percent error }=\frac{\text { approximate value }-\text {exact value}}{\text { exact value }} \times 100$$

Here, exact value = 40 and approximate value or estimated value = 50

Substituting the values in above formula,

$\begin{aligned}&\text { percent error }=\frac{50-40}{40} \times 100\\\\&\text { percent error }=\frac{10}{40} \times 100=\frac{100}{4}=25\end{aligned}$

Thus the percent error is 25 %

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3 years ago

Vol=1348.79cm³. What's X? (Height)

ale4655 [162]

V = PI x r^2 x H

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4 0

3 years ago

What is the answer for x? X+3=5

svlad2 [7]

Answer: X = 2

Step-by-step explanation: To find the value of "X" in this equation, we first need to subtract 3 from both sides.

Image provided.

3 0

3 years ago

Read 2 more answers

Please help!!As soon as possible!!

pychu [463]

Answer: Their equations have different y-intercept but the same slope

Step-by-step explanation:

Since, the slope of the line passes through the points (2002,p) and (2011,q) is,

$m_1 = \frac{q-p}{2011-2002} = \frac{q-p}{9}$

Similarly, the slope of the line asses through the points (2,p) and (11,q) is,

$m_2 = \frac{q-p}{11-2} = \frac{q-p}{9}$

Since, $m_1 = m_2$

Hence, both line have the same slope.

Now, the equation of the line one having slope $m_1$ and passes through the point (2002,p) is,

$y - p = \frac{q-p}{9}(x-2002)$

Put x = 0 in the above equation,

We get, $y = \frac{2000(p-q)}{9}+p$

The y-intercept of the line one is $(0, \frac{2000(p-q)}{9}+p)$

Also, the equation of second line having slope $m_2$ and passes through the point (2,p)

$y-p=\frac{q-p}{9}(x-2)$

Put x = 0 in the above equation,

We get, $y = \frac{2(p-q)}{9}+p$

The y-intercept of the line one is $(0, \frac{2(p-q)}{9}+p)$

Thus, both line have the different y-intercepts.

⇒ Third option is correct.

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3 years ago

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Rama09 [41]

I think 53.088 is the answer

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4 years ago