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Verizon [17]
3 years ago
5

5x3 + 14x2 + 9x help

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
6 0
<h3>Answer:    x(x+1)(5x+9) </h3>

===================================================

Work Shown:

5x^3 + 14x^2 + 9x

x( 5x^2 + 14x + 9 )

To factor 5x^2 + 14x + 9, we could use the AC method and guess and check our way to getting the correct result.

A better way in my opinion is to solve 5x^2 + 14x + 9 = 0 through the quadratic formula

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(14)\pm\sqrt{(14)^2-4(5)(9)}}{2(5)}\\\\x = \frac{-14\pm\sqrt{16}}{10}\\\\x = \frac{-14\pm4}{10}\\\\x = \frac{-14+4}{10} \ \text{ or } \ x = \frac{-14-4}{10}\\\\x = \frac{-10}{10} \ \text{ or } \ x = \frac{-18}{10}\\\\x = -1 \ \text{ or } \ x = \frac{-9}{5}\\\\

Then use those two solutions to find the factorization

x = -1  or  x = -9/5

x+1 = 0  or  5x = -9

x+1 = 0  or  5x+9 = 0

(x+1)(5x+9) = 0

So we have shown that 5x^2 + 14x + 9 factors to (x+1)(5x+9)

-----------

Overall,

5x^3 + 14x^2 + 9x

factors to

x(x+1)(5x+9)

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<h3><u>Question:</u></h3>

Cylinders A and B are similar solids. The base of cylinder A has a circumference of 4π units. The base of cylinder B has an area of 9π units.

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<h3><u>Answer:</u></h3>

Dimensions of cylinder A are multiplied by \frac{3}{2}  to produce the corresponding dimensions of cylinder B

<h3><u>Solution:</u></h3>

Cylinders A and B are similar solids.

The base of cylinder A has a circumference of 4 \pi units

The base of cylinder B has an area of 9 \pi units

Let "x" be the required factor

From given question,

Dimensions of cylinder A are multiplied by what factor to produce the corresponding dimensions of cylinder B

Therefore, we can say,

\text{Dimensions of cylinder A} \times x = \text{Dimensions of cylinder B }

<h3><u>Cylinder A:</u></h3>

The circumference of base of cylinder (circle ) is given as:

C = 2 \pi r

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Given that  base of cylinder A has a circumference of 4 \pi units

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4 \pi = 2 \pi r\\\\r = 2

Thus the dimension of cylinder A is radius = 2 units

<h3><u>Cylinder B:</u></h3>

The area of base of cylinder (circle) is given as:

A = \pi r^2

Given that,  the base of cylinder B has an area of 9 \pi units

Therefore,

\pi r^2 = 9 \pi\\\\r^2 = 9\\\\r = 3

Thus the dimension of cylinder B is radius = 3 units

\text{Dimensions of cylinder A} \times x = \text{Dimensions of cylinder B }\\\\2 \times x = 3\\\\x = \frac{3}{2}

Thus dimensions of cylinder A are multiplied by \frac{3}{2}  to produce the corresponding dimensions of cylinder B

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