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Verizon [17]
3 years ago
5

5x3 + 14x2 + 9x help

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
6 0
<h3>Answer:    x(x+1)(5x+9) </h3>

===================================================

Work Shown:

5x^3 + 14x^2 + 9x

x( 5x^2 + 14x + 9 )

To factor 5x^2 + 14x + 9, we could use the AC method and guess and check our way to getting the correct result.

A better way in my opinion is to solve 5x^2 + 14x + 9 = 0 through the quadratic formula

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(14)\pm\sqrt{(14)^2-4(5)(9)}}{2(5)}\\\\x = \frac{-14\pm\sqrt{16}}{10}\\\\x = \frac{-14\pm4}{10}\\\\x = \frac{-14+4}{10} \ \text{ or } \ x = \frac{-14-4}{10}\\\\x = \frac{-10}{10} \ \text{ or } \ x = \frac{-18}{10}\\\\x = -1 \ \text{ or } \ x = \frac{-9}{5}\\\\

Then use those two solutions to find the factorization

x = -1  or  x = -9/5

x+1 = 0  or  5x = -9

x+1 = 0  or  5x+9 = 0

(x+1)(5x+9) = 0

So we have shown that 5x^2 + 14x + 9 factors to (x+1)(5x+9)

-----------

Overall,

5x^3 + 14x^2 + 9x

factors to

x(x+1)(5x+9)

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Step-by-step explanation:

Considering the expression

2\frac{1}{32}

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\mathrm{Convert\:mixed\:numbers\:to\:improper\:fraction:}\:a\frac{b}{c}=\frac{a\cdot \:c+b}{c}

<em>Improper fraction is a fraction which has numerator greater than denominator, such as 5/3.</em>

So,

2\frac{1}{32}=\frac{2\cdot 32+1}{32}=\frac{65}{32}

As 2\frac{1}{32} is converted into improper fraction  \frac{65}{32} .

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Therefore,

2\frac{1}{32}=\frac{2\cdot 32+1}{32}=\frac{65}{32}

Keywords: fraction, reduced form, improper fraction

Learn more about fractions from brainly.com/question/535608

#learnwithBrainly

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3 years ago
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