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2 answers:
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This is an incomplete question, here is a complete question and image is also attached below.
How much longer is the hypotenuse of the triangle than its shorter leg?
a. 2 ft
b. 4 ft
c. 8 ft
d. 10 ft
Answer : The correct option is, (b) 4 ft
Step-by-step explanation:
Using Pythagoras theorem in ΔACB :
Given:
Side AC = 6 ft
Side BC = 8 ft
Now put all the values in the above expression, we get the value of side AB.
Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.
Difference = Side AB - Side AC
Difference = 10 ft - 6 ft
Difference = 4 ft
Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.
Answer:
x = 1, y = -1
Step-by-step explanation:
If we have the two equations:
and
, we can look at which variable will be easiest to eliminate.
looks like it might be easy to get rid of, we just have to multiply
by 2 and y is gone (as -6y + 6y = 0).
So let's multiply the equation by 2.
Now we can add these equations
------------------------
Dividing both sides by 5, we get .
Now we can substitute x into an equation to find y.
Hope this helped!