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tigry1 [53]
3 years ago
8

We are 95% confident that the population proportion in 2000 that supported preferential hiring of women is about 0.0509 and the

population proportion in 2010 is 0.04723. We are 95% confidence that the population proportion in 2000 that supported preferential hiring of women is between 0.0509 less to 0.04273 more than the population proportion in 2010. We are 95% confidence that the population proportion in 2010 that supported preferential hiring of women is between 0.0509 less to 0.04273 more than the population proportion in 2000. We are 95% confident that the population proportion in 2010 that supported preferential hiring of women is about 0.0509 and the population proportion in 2000 is 0.04723.
Mathematics
1 answer:
alex41 [277]3 years ago
5 0

Answer:

What do Americans think about preferential hiring of women? Has there been a change in the past decade? In 2000(group 1) and 2010(Group 2), the General Social Survey asked participants if they would favor or oppose preferential hiring of women. In 2000, out of 849 respondents, 271 said yes. In 2010, out of 696 respondents, 225 said yes. The 95% confidence interval for p1-p2 is (-0.0509, 0.04273). What would be an appropriate conclusion? O We are 95% confident that the population proportion in 2010 that supported preferential hiring of women is about 0.0509 and the population proportion in 2000 is 0.04723. We are 95% confident that the pulation proportion in 2000 that supported preferential hiring of women is about 0.0509 and the population proportion in 2010 is 0.04723. We are 95% confidence that the population proportion in 2010 that supported preferential hiring of women is between 0.0509 less to 0.04273 more than the population proportion in 2000. O We are 95% confidence that the population proportion in 2000 that supported preferential hiring of women is between 0.0509 less to 0.04273 more than the population proportion in 2010.

Step-by-step explanation:

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Answer:

1 inch

Step-by-step explanation:

The 9 is in the tenths place so you look to the hundredths place and if the number is greater than or equal to 5 then the 9 can round up.

The hundredths place is 5 so the 9 rounds up and since it can not round up in the tenths place you put the rounding in the front so the answer is 1 inch.

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3 years ago
Looking for an answer to a. please
Paladinen [302]
It's a cube so x should also equal 6
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3 years ago
Can someone please help me with this math question
inn [45]

Answer:

1. reflection across x-axis

2. translation 6 units to the right and 3 units up (x+6,y+3)

Step-by-step explanation:

The trapezoid ABCD has it vertices at points A(-5,2), B(-3,4), C(-2,4) and D(-1,2).

First transformation is the reflection across the x-axis with the rule

(x,y)→(x,-y)

so,

  • A(-5,2)→A'(-5,-2)
  • B(-3,4)→B'(-3,-4)
  • C(-2,4)→C'(-2,-4)
  • D(-1,2)→D'(-1,-2)

Second transformation is translation 6 units to the right and 3 units up with the rule

(x,y)→(x+6,y+3)

so,

  • A'(-5,-2)→E(1,1)
  • B'(-3,-4)→H(3,-1)
  • C'(-2,-4)→G(4,-1)
  • D'(-1,-2)→F(5,1)

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Answer:

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Lf x+1/x=12 then find the value of x3+1/x3​
Tresset [83]
Answer:

Explanation:

First we find what x is:
x + 1/x = 12
x + 1 = 12x
1 = 12x - x
1 = 11x
1/11 = x
Or x = 1/11

Plug x value in x^3 + 1/x^3

(1/11)^3 + 1/(1/11)^3
= (1^3/11^3)+ 1/(1^3/11^3)
= (1/1331 + 1)/1/1331
= (1/1331 + 1331/1331)/1/1331
= 1332/1331 x 1331/1
= 1332/1
= 1332

Therefore, x^3 + 1/x^3 = 1332
4 0
3 years ago
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