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tigry1 [53]
3 years ago
8

We are 95% confident that the population proportion in 2000 that supported preferential hiring of women is about 0.0509 and the

population proportion in 2010 is 0.04723. We are 95% confidence that the population proportion in 2000 that supported preferential hiring of women is between 0.0509 less to 0.04273 more than the population proportion in 2010. We are 95% confidence that the population proportion in 2010 that supported preferential hiring of women is between 0.0509 less to 0.04273 more than the population proportion in 2000. We are 95% confident that the population proportion in 2010 that supported preferential hiring of women is about 0.0509 and the population proportion in 2000 is 0.04723.
Mathematics
1 answer:
alex41 [277]3 years ago
5 0

Answer:

What do Americans think about preferential hiring of women? Has there been a change in the past decade? In 2000(group 1) and 2010(Group 2), the General Social Survey asked participants if they would favor or oppose preferential hiring of women. In 2000, out of 849 respondents, 271 said yes. In 2010, out of 696 respondents, 225 said yes. The 95% confidence interval for p1-p2 is (-0.0509, 0.04273). What would be an appropriate conclusion? O We are 95% confident that the population proportion in 2010 that supported preferential hiring of women is about 0.0509 and the population proportion in 2000 is 0.04723. We are 95% confident that the pulation proportion in 2000 that supported preferential hiring of women is about 0.0509 and the population proportion in 2010 is 0.04723. We are 95% confidence that the population proportion in 2010 that supported preferential hiring of women is between 0.0509 less to 0.04273 more than the population proportion in 2000. O We are 95% confidence that the population proportion in 2000 that supported preferential hiring of women is between 0.0509 less to 0.04273 more than the population proportion in 2010.

Step-by-step explanation:

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A school authority claims that the average height of students is 178 cm. A researcher has taken a well-designed survey and his s
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Answer:

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Step-by-step explanation:

From the given information:

Population mean = 178 cm

the sample mean = 177.5 cm

the standard deviation = 2

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The null hypothesis and the alternative hypothesis can be computed as:

Null hypothesis:

H_o: \mu = 178

Alternative hypothesis:

H_1: \mu \neq 178

The t-test statistics is determined by using the formula:

t = \dfrac{X - \mu}{\dfrac{\sigma}{\sqrt{n}}}

t = \dfrac{177.5 - 178}{\dfrac{2}{\sqrt{25}}}

t = \dfrac{-0.5}{\dfrac{2}{5}}}

\mathbf{t= -1.25}

Degree of freedom df = n- 1

Degree of freedom df = 25 - 1

Degree of freedom df = 24

At the level of significance ∝ = 0.05, the critical value  = 2.064

Decision rule: To reject the null hypothesis if the test statistics  is greater than the critical value at 0.05 level of significance

Conclusion: We fail to reject the null hypothesis since the test statistics is lesser than the critical value and we conclude that  the difference exists due to chance since the test statistic is small

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

We need to write equations to solve

Let the two numbers be x and y

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