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2 years ago

Lowest common multiple of 6 and 21

Mathematics

2 answers:

Yanka [14]2 years ago

7 0

Answer:

my bad it is 42

Step-by-step explanation:

MrRa [10]2 years ago

6 0

Answer:

it's 42!!!!

Step-by-step explanation:

2*3 and 7*3

3*14=42

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Find the values of x and y

arsen [322]

Answer:

x=18√6 , y=36√2

Step-by-step explanation:

${z}^{2} = 18 {}^{2} + 18 {}^{2} - 2(18)(18) \cos(90 ) \\ z = 18 \sqrt{2 } \\ \frac{x}{ \sin(60) } = \frac{z}{ \sin(30) } \\ x = 18 \sqrt{6} \\ \frac{y}{ \sin(90) } = \frac{z}{ \sin(30) } \\ y = 36 \sqrt{2}$

7 0

2 years ago

Solve the following system of equations by linear combination: 3x+2y=7 y=x-4

ki77a [65]

Answer : (3,-1) Hoped this helped :)

4 0

2 years ago

Read 2 more answers

Sesame Company purchased a computer system for $74,000 on January 1, 2018. It was depreciated based on a 7-year life and an $18,

amm1812

Answer: $24000

Step-by-step explanation:

Depreciation for 2018 = ($74,000 - $18000) / 7

= $56000/7

= $8000

Depreciation for 2019 = ($74,000 - $18000) / 7

= $56000/7

= $8000

Depreciation up to 2019 = $8000 + $8000 = $16000

Book value at end of 2019 = $74000 - $16000 = $58000

Revised residual value = $10,000

Number of remaining years = 4-2 = 2 years

Depreciation expensed for 2020 will be:

= ($58000 - $10,000) / 2

= $48000/2

= $24000

7 0

2 years ago

PLEASE HELP!

Marina86 [1]

Answer:

(x + 2) + (–5x + 4) / (x² – 2x + 1)

Step-by-step explanation:

(x³ – 8 x + 6) ÷ (x² – 2x + 1)

The operation can be carried out as follow:

Please see attached photo for details.

(x³ – 8 x + 6) ÷ (x² – 2x + 1) =

(x + 2) + (–5x + 4) / (x² – 2x + 1)

4 0

2 years ago

14. A company uses many different delivery

ziro4ka [17]

Answer:

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Sent by ABC Speedy Delivery Service.

Event B: Arrived on time.

The probability that any given parcel will be sent by the ABC Speedy Delivery Service is 0.71.

This means that $P(A) = 0.71$

The probability that the parcel will arrive on time given the ABC Speedy Delivery Company was used is 0.93.

This means that $P(B|A) = 0.93$

Find the probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

This is $P(A \cap B)$ . So

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

$P(A \cap B) = P(B|A)*P(A) = 0.93*0.71 = 0.6603$

0.6603 = 66.03% probability that it will be sent with the ABC Speedy Delivery Company and arrive on time.

8 0

2 years ago