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alex41 [277]
4 years ago
6

Which equation is equivalent to

Mathematics
1 answer:
slega [8]4 years ago
4 0

Answer:

B

Step-by-step explanation:

You might be interested in
a. it is a multiple of 3,b. is greater then 100 ,c. it is not even, d.all digits are odd. whats the number?
uranmaximum [27]

Answer:

333.

Step-by-step explanation:

3•111=333

333>100

All the digits are odd...


4 0
3 years ago
Find<br>Sin 2 (30degrees)<br>​
Vinvika [58]

Answer:

<em>Sin 2 (30)°=  </em>\frac{\sqrt{3} }{2}

Step-by-step explanation:

<u><em>Explanation:-</em></u>

<em>Given that   Sin 2 (30)°</em>

<em>we know that the formula  sin2θ = 2sinθ cosθ</em>

<em>    Given that θ = 30</em><em>° </em>

<em>    Now  </em>

<em>          sin2(30)° = 2sin30° cos30°</em>

<em>                                              </em>= 2 ( \frac{1}{2} X \frac{\sqrt{3} }{2} )<em> </em>

<em>        After cancellation, we get</em>

<em>                            Sin 2 (30)° = </em>\frac{\sqrt{3} }{2}

<u><em>Final answer:-</em></u>

<em>           Sin 2 (30)° = </em>\frac{\sqrt{3} }{2}<em>    </em>

<em></em>

5 0
3 years ago
Sam and Annika ride their bikes to school. Sam rides his bike (K )kilometers. Annika rides her bike two less than four times as
Gekata [30.6K]
S=k, a=4k-2

Annika rides her bike so she must travel some positive distance, ie a>0 so:

4k-2>0

4k>2

k>1/2  and that k is how far Sam rode, so Sam must ride his bike more than 1/2 kilometer.
7 0
4 years ago
The spherical balloon is inflated at the rate of 10 m³/sec. Find the rate at which the surface area is increasing when the radiu
rjkz [21]

The balloon has a volume V dependent on its radius r:

V(r)=\dfrac43\pi r^3

Differentiating with respect to time t gives

\dfrac{\mathrm dV}{\mathrm dt}=4\pi r^2\dfrac{\mathrm dr}{\mathrm dt}

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

10\dfrac{\mathrm m^3}{\mathrm s}=4\pi (3\,\mathrm m)^2\dfrac{\mathrm dr}{\mathrm dt}\implies\dfrac{\mathrm dr}{\mathrm dt}=\dfrac5{18\pi}\dfrac{\rm m}{\rm s}

The surface area of the balloon is

S(r)=4\pi r^2

and differentiating gives

\dfrac{\mathrm dS}{\mathrm dt}=8\pi r\dfrac{\mathrm dr}{\mathrm dt}

so that at the moment the radius is 3 m, its area is increasing at a rate of

\dfrac{\mathrm dS}{\mathrm dt}=8\pi(3\,\mathrm m)\left(\dfrac5{18\pi}\dfrac{\rm m}{\rm s}\right)=\dfrac{20}3\dfrac{\mathrm m^2}{\rm s}

4 0
3 years ago
Help as soon as possible please!!
Tasya [4]

Answer:

i think its statstic not sure tho

Step-by-step explanation:

8 0
3 years ago
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