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2 years ago

Write two mixed numbers that have a sum of 3

2 answers:

3 0

1.5 and 1.5 equals 3. 1.5+1.5=3
one plus one equals two and point five plus point five equals one, so one plus two equals three.
1+2=3

astra-53 [7]2 years ago

3 0

(1 1/2) + (1 1/2) = 3

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Gennadij [26K]

Answer: I don't believe i understand.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help (Its multiple choice)

artcher [175]

Step-by-step explanation:

-5(4a) = (-5a)4

(By commutative property of multiplication)

4 0

3 years ago

Read 2 more answers

Find all possible values of α+

const2013 [10]

Answer:

$\rm\displaystyle 0,\pm\pi$

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when tanα+tanβ+tanγ = tanαtanβtanγ to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \alpha ) \tan( \beta ) \tan( \gamma ) - \tan( \gamma )$

factor out tanγ:

$\rm\displaystyle \tan( \alpha ) + \tan( \beta ) = \tan( \gamma ) (\tan( \alpha ) \tan( \beta ) - 1)$

divide both sides by tanαtanβ-1 and that yields:

$\rm\displaystyle \tan( \gamma ) = \frac{ \tan( \alpha ) + \tan( \beta ) }{ \tan( \alpha ) \tan( \beta ) - 1}$

multiply both numerator and denominator by-1 which yields:

$\rm\displaystyle \tan( \gamma ) = - \bigg(\frac{ \tan( \alpha ) + \tan( \beta ) }{ 1 - \tan( \alpha ) \tan( \beta ) } \bigg)$

recall angle sum indentity of tan:

$\rm\displaystyle \tan( \gamma ) = - \tan( \alpha + \beta )$

let α+β be t and transform:

$\rm\displaystyle \tan( \gamma ) = - \tan( t)$

remember that tan(t)=tan(t±kπ) so

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm k\pi )$

therefore when k is 1 we obtain:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta\pm \pi )$

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm \pi )$

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

$\rm\displaystyle \gamma = - \alpha - \beta \pm \pi$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ \pm \pi }$

when is 0:

$\rm\displaystyle \tan( \gamma ) = -\tan( \alpha +\beta \pm 0 )$

likewise by Opposite Angle Identity we obtain:

$\rm\displaystyle \tan( \gamma ) = \tan( -\alpha -\beta\pm 0 )$

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

$\rm\displaystyle \gamma = - \alpha - \beta \pm 0$

isolate -α-β to left hand side and change its sign:

$\rm\displaystyle \alpha + \beta + \gamma = \boxed{ 0 }$

and we're done!

8 0

3 years ago

Read 2 more answers

What is the inverse of the function f(x) = 8x+1

Yanka [14]

Answer:

f⁻¹(x) = (x - 1)/8

f⁻¹(x) = 1/8 x - 1/8

Step-by-step explanation:

To find the inverse of a function, switch the "x" and "y" variables, then isolate "y".

Remember "f(x)" is the same thing as "y". Change from function notation to "y".

f(x) = 8x + 1

y = 8x + 1

Switch the "x" and "y" variables

x = 8y + 1

Isolate "y". Move the "y" variable to the left for standard formatting

8y + 1 = x

8y + 1 - 1 = x - 1 Subtract 1 from both sides

8y = x - 1

$\frac{8y}{8}=\frac{x-1}{8}$ Divide both sides by 8 and simplify

$y=\frac{x-1}{8}$ Inverse equation

$y=\frac{1}{8}x-\frac{1}{8}$ Slope-intercept form

Use function notation, change "y"

$f^{-1}(x)=\frac{x-1}{8}$ Simplified

$f^{-1}(x)=\frac{1}{8}x-\frac{1}{8}$ Slope-intercept form

6 0

2 years ago

Hi,

lyudmila [28]

Here I have answered your question. Hope this helps. pls give brainliest if possible. tks. Have a nice day!!

3 0

2 years ago