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alekssr [168]
3 years ago
12

If an object is reflected twice over parallel line and corresponding points of the original and final translation image are 26 c

entimeters apart, how far apart are the parallel lines
Mathematics
1 answer:
Airida [17]3 years ago
5 0
By definition, when an object is reflected twice over parallel lines, the distance between the points of the original object and the the point of the final translation of the object, is twice the distance between the two parallel lines. Keeping this information on mind, you have:
 The distance between <span>points of the original and final translation image is 26 centimeters. Therefore:
 2d=26 cm
 d=26 cm/2
 d=13 cm
 Therefore, the answer is: 13 cm.</span>
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Given klmn is a trapezoid, kl = mn, m&lt;1 = m&lt;2, lm/kn = 8/9, pklmn = 132. Find: the length of the legs
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Answer:

The length of legs lm, mn, and lk is 32 while that of kn is 36.

Step-by-step explanation:

The diagram is attached in the answer.

As both the angles are equal thus the two forms isosceles triangles. This is true because the converse of base angle theorem is applicable here. The theorem clearly states that when a trapezoid is divided by the diagonal, it forms two set of angles where m<1=m<2 and m<lmk=m<nmk

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mn=lm\\

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mn=8x

Now the perimeter is given as

\text{perimeter}=lm+mn+kn+lk\\

Here perimeter is given as 132 so this gives:

\text{perimeter}=lm+mn+kn+lk\\132=8x+8x+8x+9x\\132=33x\\x=\dfrac{132}{33}\\x=4

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lm=8x=8\times 4=32\\mn=8x=8\times 4=32\\lk=8x=8\times 4=32\\kn=9x=9\times4=36

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