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baherus [9]
3 years ago
12

×square minus3× minus 10=0

Mathematics
1 answer:
nika2105 [10]3 years ago
6 0
X²-3x-10=0
x²-(5-2)x-10=0
x²-5x+2x-10=0
x(x-5)+2(x-5)
(x-5)(x+2)
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PLEASE HELP ME ! IMAGE IS BELOW IF YOU GET IT RIGHT I'LL MARK BRAINLIEST
jarptica [38.1K]

Answer:

x = 17

y = 8

QPR = 35º

QRP = 60º

Step-by-step explanation:

2x + 1 = x + 18

Subtract x from both sides

x + 1 = 18

Subtract 1 from both sides

x = 17

QPR = 2x + 1

QPR = 2(17) + 1

QPR = 35º

-------------------------------

8y - 4 = 4y + 28

Subtract 4y from both sides

4y - 4 = 28

Add 4 to both sides

4y = 32

Divide both sides by 4

y = 8

QPR = 8y - 4

QRP = 8(8) - 4

QRP = 60º

7 0
3 years ago
Find the value of (X)<br> The subject is polygons.
Rudik [331]

Please delete this answer.

3 0
3 years ago
Jessie draws triangle ABC on a coordinate grid. The slope of line segment AB is Jessie then transforms triangle
balu736 [363]

Answer:

1) Supports Jessie's Claim

2) Does Not Support Jessi's Claim

3) Supports Jessie's Claim

4) Does Not Support Jessi's Claim

Step-by-step explanation:

The given transformations are;

1) Rotation of 180° around the origin

For a rotation of 180° around the origin, either clockwise or anti clockwise, for a given coordinate of the preimage (x, y), the coordinate of the image is (-x, -y)

Therefore, whereby the slope of the preimage, given two points (0, 0) and (2, 2), = (2 - 0)/(2 - 0) = 1

For the image with the points (0, 0) and (-2, -2), we have;

(-2 - 0)/(-2 - 0) = 1

Therefore, the slope of the preimage and the image are equal

Therefore, supports Jessie's Claim

2) For a reflection across the line y = 2, we have

We note that the line y = 2 is parallel to the x-axis

For a reflection across the x-axis, for a preimage (x, y), we have the coordinates of the image (x, -y)

However for the reflection across the line y = 2, we have;

For a preimage, (x, y), the coordinate of the image is (x, -y+4)

Given two points, of the preimage (0, 0) and (2, 2), we have the image given as (0, 4) and (2, -2 + 4) = (2, 2);

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (2 - 4)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

3) For a translation up 1.25 units, we note that the difference in the y and x values of the coordinates of the preimage and the image will be equal when finding the slope, and therefore, the slope of the figure of the preimage and the slope of the figure of the image will be equal

Therefore, supports Jessie's Claim

4) For a reflection across the x-axis, a point on the preimage, with coordinates (x, y) will form a point on the image with coordinates (x, - y)

For a preimage with points (0, 0) and (2, 2), we have the image as (0, 0) and (2, -2)

The slope of the preimage is (2 - 0)/(2 - 0) = 1

The slope of the image is (-2 - 0)/(2 - 0) = -1

The slope of the line of the preimage and the image are different

Therefore, does Not Support Jessi's Claim

6 0
3 years ago
Which graph decreases, crosses the y-axis at (0,-7), and then remains constant?
sergey [27]

Answer:

A.Graph B

Step-by-step explanation:

it decreases to a y of (0,-7) and then stays constant at -7

Hope this was helpful

7 0
3 years ago
25
Cloud [144]
If you are asking if your work is good,thn yes,you are right

7 0
3 years ago
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