4 years ago

6(x-5) = 5(x+5)

Mathematics

1 answer:

Mariana [72]4 years ago

4 0

Part 1:

6(x-5) = 5(x+5) (x = 55)

4y + 2 (-3 + 2y) = 1-y (x = 7/9)

Part 2:

4(a-6) = 8a - (4a-24) (No Solution)

4(2x-8) = 8(x-8) (No Solution)

2(3x-3) = -6x-6 (Identity (x = 0))

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If 5x-26=x+50, then the value of x is

horsena [70]

Let's work this problem out!

First: 5(x) - 26 - x + 50 = ?

Second: 4(x) - 76 = ?

Third: 4 = ?
↑
(Solve Step 3)

Fourth: x - 19 = 0
↑
(Add the number 19 to each of your sides for Step 4)

Finally we get to your answer

19 + 0 = 19 ; 19 - 19 = 0

So, therefore the value of "x" is 19

$x = 19$

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Answer:

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Write an expression that equals to 100 and only uses the number 3. You can use exponents and parentheses but the exponent must e

Liono4ka [1.6K]

33+33+3^0 = 100
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3 years ago

(-b3+ 3b2 + 8) - (? - 5b2 - 9) = 5b3 + 8b2 + 17<br> ? =<br> DONE

zhuklara [117]

Let's solve for x.

−b3+3b2+8−(x−5b2−9)=5b3+8b2+17

Step 1: Add b^3 to both sides.

−b3+8b2−x+17+b3=5b3+8b2+17+b3

8b2−x+17=6b3+8b2+17

Step 2: Add -8b^2 to both sides.

8b2−x+17+−8b2=6b3+8b2+17+−8b2

−x+17=6b3+17

Step 3: Add -17 to both sides.

−x+17+−17=6b3+17+−17

−x=6b3

Step 4: Divide both sides by -1.

−x

−1

6b3

−1

x=−6b3

Answer:

x=−6b3

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4 years ago

Read 2 more answers

Describe the quadrilateral???....<br> It is a rectangle? and what else?

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Last time I checked- it was a rhombus.

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