Ask question

Ask question

All categories

2 years ago

12

Lucy purchased a prepaid phone card for $30. Long distance calls cost 21 cents a minute using this card. Lucy used her card only

once to make a long distance call. If the remaining credit on her card is $27.27, how many minutes did her call last?

1 answer:

Alisiya [41]2 years ago

8 0

Answer:

129.8 mins

Step-by-step explanation:

27.27/21 = 129.8

You might be interested in

Round 3,854,927 to the hundredths place

Tamiku [17]

Answer: 3854927

Step-by-step explanation: Becuase I smart

6 0

2 years ago

(2x+5)(6x−1)=120<br><br> dbdjkslssllalammsbdjfkf

spin [16.1K]

Answer: x = 115/2 and 119/6

You can simplify the answer.

Step-by-step explanation:

(2x + 5)(6x -1)= 120

120 = (2x +5) and (6x -1) = 120

120 - 5 = 2x and 6x = 120 - 1

115 = 2x and 6x = 119

115/2 = x and x = 119/6

8 0

2 years ago

Read 2 more answers

Graph the inequality below on the number line.

marshall27 [118]

Answer:

You start at -9

-Open circle

-shade towards the right (where all the positive numbers are)

Open circle - ones that don't have a greater than or equal to. If it does then it's a closed one.

Shade towards the right cause y is less than 9

3 0

2 years ago

Read 2 more answers

8x+15≤51 slove.PLEASE HELP MEEEEEEEEEEEEEEE

inysia [295]

Answer:

x≤9/2

Step-by-step explanation:

8x+15≤51

Subtract 15

8x+15-15≤51-15

8x+≤36

Divide by 8

8x/8≤36/8

x≤9/2

7 0

2 years ago

Find out the number of combinations and the number of permutations for 8 objects taken 6 at a time. Express your answer in exact

umka2103 [35]

Solution:

The permutation formula is expressed as

$\begin{gathered} P^n_r=\frac{n!}{(n-r)!} \\ \end{gathered}$

The combination formula is expressed as

$\begin{gathered} C^n_r=\frac{n!}{(n-r)!r!} \\ \\ \end{gathered}$

where

$\begin{gathered} n\Rightarrow total\text{ number of objects} \\ r\Rightarrow number\text{ of object selected} \end{gathered}$

Given that 6 objects are taken at a time from 8, this implies that

$\begin{gathered} n=8 \\ r=6 \end{gathered}$

Thus,

Number of permuations:

$\begin{gathered} P^8_6=\frac{8!}{(8-6)!} \\ =\frac{8!}{2!}=\frac{8\times7\times6\times5\times4\times3\times2!}{2!} \\ 2!\text{ cancel out, thus we have} \\ \begin{equation*} 8\times7\times6\times5\times4\times3 \end{equation*} \\ \Rightarrow P_6^8=20160 \end{gathered}$

Number of combinations:

$\begin{gathered} C^8_6=\frac{8!}{(8-6)!6!} \\ =\frac{8!}{2!\times6!}=\frac{8\times7\times6!}{6!\times2\times1} \\ 6!\text{ cancel out, thus we have} \\ \frac{8\times7}{2} \\ \Rightarrow C_6^8=28 \end{gathered}$

Hence, there are 28 combinations and 20160 permutations.

7 0

8 months ago