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Kipish [7]
3 years ago
14

Two technicians are discussing potentiometers. Technician A says that most potentiometers use a supply wire, ground wire, and a

signal wire. Technician B says that potentiometers should show a relatively smooth increase and decrease of voltage when moved through its range of motion. who is correct?
SAT
1 answer:
Likurg_2 [28]3 years ago
5 0

technician b is correct because potentiometers dont need a power supply to work

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It’s Obama obviously
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4 years ago
A study suggests that about 80\%80%80, percent of undergraduate students are working at a job. Researchers plan to do a follow-u
Leni [432]

Using the z-distribution, it is found that the smallest sample size required to obtain the desired margin of error is of 4330.

<h3>What is a confidence interval of proportions?</h3>

A confidence interval of proportions is given by:

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which:

  • \pi is the sample proportion.
  • z is the critical value.
  • n is the sample size.

The margin of error is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem:

  • The estimate of the proportion is of \pi = 0.8.
  • The desired margin of error is of M = 0.01.
  • 90% confidence level, hence\alpha = 0.9, z is the value of Z that has a p-value of \frac{1+0.9}{2} = 0.95, so z = 1.645.

Then, we solve for n to find the minimum sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 1.645\sqrt{\frac{0.8(0.2)}{n}}

0.01\sqrt{n} = 1.645\sqrt{0.8(0.2)}

\sqrt{n} = \frac{1.645\sqrt{0.8(0.2)}}{0.01}

(\sqrt{n})^2 = \left(\frac{1.645\sqrt{0.8(0.2)}}{0.01}\right)^2

n = 4329.6

Rounding up, the smallest sample size required to obtain the desired margin of error is of 4330.

To learn more about the z-distribution, you can take a look at brainly.com/question/12517818

7 0
2 years ago
Two small metal cubes with masses 2. 0 g and 4. 0 g are tied together by a 5. 0-cm-long massless string and are at rest on a fri
Aleks04 [339]

The energy of the system, tension in the string, and speed of each cube are respectively; U = 0.72 J, T = 14 N and (V₂, V₄) = (-22, 14)

<h3>Calculation of energy and tension in a String</h3>

We are given;

Mass of cube 1; m₁ = 2 g

Mass of cube 2; m₂ = 4 g

Distance between cubes; d = 5 cm = 0.05 m

Charges of cubes; Q = q = +2. 0 μc = 2.0 × 10⁻⁶ C

A) Formula for the energy of the system is;

U = kQq/d

U = 8.99 × 10⁹ × (2.0 × 10⁻⁶ C)²/0.05 m

U = 0.03596/0.05

U = 0.72 J

B) Formula for the Tension is;

T = U/d

T = 0.72/0.05

T ≈ 14 N

C) Momentum is conserved, and as such the initial momentum is zero. Thus;

0 = (0.0020 × V₂) + (0.0040 × V₄)

⇒ V₂ = -2V₄

Energy is also conserved and so;

(½ × 0.0020 × (-2V₄)²) + (½ × 0.004 × (V₄)²) = 0.72 J

-0.0040V₄² + 0.002V₄² = 0.72 J

0.0060V₄² = 0.72 J

V₄² = 0.72/0.0060

V₄² = 120

V₄ = √120

V₄ ≈ 11 m/s

Recall that; V₂ = -2V₄

Thus;

V₂ = -2(11) m/s

V₂ = -22 m/s

Thus;

(V₂, V₄) = (-22, 14)

Read more about Conservation of Momentum at; brainly.com/question/7538238

8 0
3 years ago
Decomposers turn detritus to _______ which then get assimilated by producers.
vazorg [7]
Decomposers turn detritus to soil which then get assimilated by producers. The process is used by plants to create glucose
7 0
3 years ago
Based on the chart below, which of the following statements is true?
MissTica

Answer:

definitely D

Explanation:

there is literally no evidence of air pressure in the chart at all

6 0
3 years ago
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